Analysis of the effect of lectin using chi-square analysis In science, it is not sufficient to say "My results look pretty good.
More cells treated with lectin are in mitosis compared to those in the control, which supports my hypothesis that lectin is a growth promoter." A valid conclusion must be supported by appropriate statistical analysis. In this activity, the appropriate tool is the chi-square test. Because this test can be applied across many different situations, your instructor will introduce you to it when appropriate for your course. In chi-square analysis, you always begin with a null hypothesis. The null hypothesis states that there is no statistically significant difference between the results in the control group compared to the experimental group. If the null hypothesis is rejected (a null hypothesis is either rejected or not rejected) because variation between the control group and experimental group is too great, this lends support to an experimental hypothesis. In this case, the experimental hypothesis was that lectin is a growth promoter.If you do a chi-square analysis of the results of a study to compare the number of cells in interphase versus those in mitosis for both lectin-treated and untreated cells, which of the following would represent an appropriate null hypothesis?A. If lectin promotes cell division, then more cells will be in interphase than in mitosis when compared to a control. B. There should be no significant difference between the cells in interphase versus those in mitosis in the two treatments. C. There should be a significant difference between the cells in interphase versus those in mitosis in the two treatments. D. If lectin promotes cell division, then more cells will be in mitosis than in interphase when compared to a control.
<span>They are both sites of new cell formation. They both contain structures that assist the body in cooling down if overheating occurs. They both contain or are associated with sensory neurons. </span>
