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Law Incorporation [45]
2 years ago
6

What is the volume of the prism?

Mathematics
1 answer:
Nikitich [7]2 years ago
7 0

Answer:

24 m³

Step-by-step explanation:

We need to find the volume of the prism. Given that , rectangular prism with cubic units arranged in two rows of two with six total layers . And the volume of each unit is 1 m³ .

<u>Volume</u><u> of</u><u> </u><u>one</u><u> </u><u>unit </u><u>:</u><u>-</u><u> </u>

\rm\implies Volume_{one\ unit } = 1m^3

<u>By </u><u>Unitary</u><u> Method</u><u> </u><u>:</u><u>-</u><u> </u>

Volume of two cubes , will be :-

\rm\implies Volume_{two\ unit } = 2m^3

<u>Volume</u><u> of</u><u> </u><u>one </u><u>layer </u><u>:</u><u>-</u><u> </u>

\rm\implies Volume_{one\ layer } = 4m^3

<u>Volume</u><u> of</u><u> </u><u>six </u><u>layers </u><u>:</u><u>-</u><u> </u>

\rm\implies Volume_{6\ layers } = 4m^3\times 6 \\\\\rm\implies \boxed{\rm Volume_{6\ layers } = 24 \ m^3}

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Answer:

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Step-by-step explanation:

Given that  h(x)=f(f(x))

now to find h(x)=f(f(x)) from the given functions f(x) and f'x

let h(x)=f(f(x))

Then put x=1 in above function we get

h(1)=f(f(1))

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Therefore h(1)=6

Now to find h'(1)

Let

h^{\prime}(x)=f^{\prime}(f^\prime(x)) (since  h(x)=f(f(x)) )

put x=1 in above function we get

h^{\prime}(1)=f^{\prime}(f^\prime(1))

=f^{\prime}(2)    (From the table f^\prime(1)=2 and f^\prime(2)=5)

h^{\prime}(1)=5

Therefore h^{\prime}(1)=5

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3 years ago
#1. Which is equal to z3 8? A. (z - 2)(z^2 - 2z - 4). B. (z + 2)(z^2 - 2z + 4) C.(z - 2)(z^2+ 2z + 4). D. (z + 2)(z^2+ 2z - 4) #
tankabanditka [31]
#1. B
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<span>(x - 7)(x + 7)(x- 2)
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#5. C
(y - 4) = 0
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#6. A and B
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