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vekshin1
3 years ago
15

Simplify the following expression.

Mathematics
1 answer:
tankabanditka [31]3 years ago
7 0
The answer is 2/3

or in decimal form: 0.6 repeated
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1. Angle BAC = 35° and angle BCA = 20°. What is the measure of angle BAD?
Tema [17]

Check the picture below.

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2 years ago
wade wants to buy sweaters. He has $175 and each sweater costs $12.00. Write and solve an inequality to find how many sweaters h
Hatshy [7]
Wade wants to have at least $55 left, so the sign will be ≤ (greater than or equal to 55) One sweater costs $12. You can use x to represent an unkown number of sweaters, so $12x. You are subtracting 12x by your budget of $175. When put together, the inequality is $175-$12x ≤ $55. Now to solve. You want to get x alone so subtract 175. You must do this to both sides. Now you have -12x≤ -120. Divide both sides by -12 and your final answer is -120/-12 ≥ 10. (Notice the sign changes when you divide by a negative) So Wade cannot buy more than 10 sweaters to have $55 left over. Phoo that was a workout. It can be difficult but once you get the hang of it it comes easy. If you need more help just ask :D
8 0
3 years ago
Read 2 more answers
There are 4 circles and 2 squares. What is the simplest ratio of squares to circles?
stiv31 [10]

Answer:

1:2

Step-by-step explanation:

it asks for it in the order of squares to circles, and wants it in simplest form. 4 and 2 are both divisible by two, so its now 2 and 1. so now, you have to put the square number first, and the circle second. So, it is 1:2

8 0
4 years ago
Verify cot x sec^4x=cotx +2tanx +tan^3x
Tanzania [10]

Answer:

See explanation

Step-by-step explanation:

We want to verify that:

\cot(x)  \:  { \sec}^{4} x =  \cot(x) + 2 \tan(x)   +  { \tan}^{3} x

Verifying from left, we have

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \: ( 1 +  { \tan}^{2} x )^{2}

Expand the perfect square in the right:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \: ( 1 +  { 2\tan}^{2} x  + { \tan}^{4} x)

We expand to get:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \:   +  \cot(x){ 2\tan}^{2} x  +\cot(x) { \tan}^{4} x

We simplify to get:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \:   +  2 \frac{ \cos(x) }{\sin(x) ) }  \times  \frac{{ \sin}^{2} x}{{ \cos}^{2} x}   +\frac{ \cos(x) }{\sin(x) ) }  \times  \frac{{ \sin}^{4} x}{{ \cos}^{4} x}

Cancel common factors:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \:   +  2 \frac{{ \sin}x}{{ \cos}x}   +\frac{{ \sin}^{3} x}{{ \cos}^{3} x}

This finally gives:

\cot(x)  \:  { \sec}^{4} x =  \cot(x) + 2 \tan(x)   +  { \tan}^{3} x

3 0
4 years ago
5x < 30 what is it equal to?
dybincka [34]
Five times < thirty is readily equal to six
6 0
4 years ago
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