Answer:

Step-by-step explanation:
Given:

We want to determine the value of 
First, we evaluate h(-1)

Therefore: 

Therefore: f(h(-1))=-11
Answer:
Absolute value equations are equations where the variable is within an absolute value operator, like |x-5|=9. The challenge is that the absolute value of a number depends on the number's sign: if it's positive, it's equal to the number: |9|=9. If the number is negative, then the absolute value is its opposite: |-9|=9.
Step-by-step explanation:
#1
9^2-1
(9×9)-1
81-1
80
#2
10(19-4^2)
10(19-16)
10(3)
30
Ones,tenths,hundreths, thousands,tenthousands,hundredthousands
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Hope this helps :)