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Ksju [112]
4 years ago
7

Brainiest to who answers

Mathematics
2 answers:
anyanavicka [17]4 years ago
7 0

Answer:

x-intercept (20/3, 0)

Y-intercept (0,10)

Step-by-step explanation:

ZanzabumX [31]4 years ago
6 0
The answer is in the picture

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If the mean of 12,16,22,X 28 is 19.6 find X
vodomira [7]

Answer:

20

Step-by-step explanation:

A data is given and the mean of data is 19.6 .The data is ,

12 , 16 , 22 , x , 28 .

We know that the mean is sum of observations divided by Total number of observations . So that ,

⇒ 12 + 16 + 22 + x + 28/ 5 = 19.6

⇒ 78+x/5 = 19.6

⇒ 19.6 × 5 = 78 + x

⇒ 78 + x = 98

⇒ x = 98 - 78

⇒ x = 20

<h3><u>Hence </u><u>the</u><u> value</u><u> of</u><u> </u><u>x</u><u> </u><u>is</u><u> </u><u>2</u><u>0</u><u> </u><u>.</u></h3>
6 0
3 years ago
(27a⁶b³c⁹)⅓<br> How to solve
LenaWriter [7]

Answer:

9a⁶b³c⁹

Step-by-step explanation:

Just divide the 27 by 3 since 27a⁶b³c⁹ is a single number

8 0
4 years ago
PLEASE HELP ME
Mamont248 [21]

Answer:

Reflection in the x-axis followed by a translation 5 units left and 1 unit up

Step-by-step explanation:

The coordinates of X are (-6,2).

When we reflect in the x-axis we get X'=(-6,-2)

When we translate by the rule T(x-5,y+1), we get X"=(-6-5,-2+1)=(-11,-1)

The coordinates of Y are (-4,7).

When we reflect in the x-axis we get Y'=(-4,-7)

When we translate by the rule T(x-5,y+1), we get Y"=(-4-5,-7+1)=(-9,-6)

The coordinates of Z are (-2,2).

When we reflect in the x-axis we get Z'=(-2,-2)

When we translate by the rule T(x-5,y+1), we get Z"=(-2-5,-2+1)=(-7,-1)

Therefore the sequence of transformation is a reflection in the x-axis followed by a translation 5 units left and 1 unit up.

5 0
3 years ago
Free points, please solve -2m+36=2(6m-3)?​
Elan Coil [88]

Answer:

\Huge \boxed{m=3}

Step-by-step explanation:

-2m+36=2(6m-3)

Expanding brackets.

-2m+36=12m-6

Adding 2m and 6 to both sides.

36+6=12m+2m

Combining like terms.

42=14m

Dividing both sides by 14.

3=m

8 0
3 years ago
Read 2 more answers
fourth,sixth and thirteenth term in this sequence A(n)= 6+(n+1)(-2) help me to find and describe the explicite formula
OleMash [197]
Hello,

A(n)=6+(n+1)^(-2)=6+1/(n+1)²

A_{4} =6+ \dfrac{1}{(4+1)^2} =6+ \dfrac{1}{25}= \dfrac{151}{25} \\&#10;&#10; A_{6} =6+ \dfrac{1}{(6+1)^2} =6+ \dfrac{1}{49}= \dfrac{295}{49} \\&#10;&#10; A_{13} =6+ \dfrac{1}{(13+1)^2} =6+ \dfrac{1}{196}= \dfrac{1177}{196} \\&#10;
7 0
4 years ago
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