What are the zeros of the polynomial function f(x) = (x)(x - 6)(x + 4)?

Mathematics

1 answer:

erik [133]2 years ago

7 0

The zeros are 0, 6, -4

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2 years ago

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3 years ago

Urgent. Please show all work

myrzilka [38]

Answer:

$\displaystyle f'(x) = \frac{4}{x^2}$

General Formulas and Concepts:

<u>Calculus</u>

Limits

Limit Rule [Variable Direct Substitution]: $\displaystyle \lim_{x \to c} x = c$

Differentiation

Derivatives
Derivative Notation

The definition of a derivative is the slope of the tangent line: $\displaystyle f'(x) = \lim_{h \to 0} \frac{f(x + h) - f(x)}{h}$

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify.</em>

<em /> $\displaystyle f(x) = -\frac{4}{x}$

<u>Step 2: Differentiate</u>

[Function] Substitute in <em>x</em>: $\displaystyle f(x + h) = -\frac{4}{x + h}$
Substitute in functions [Definition of a Derivative]: $\displaystyle f'(x) = \lim_{h \to 0} \frac{-\frac{4}{x + h} - \big( -\frac{4}{x} \big)}{h}$
Simplify: $\displaystyle f'(x) = \lim_{h \to 0} \frac{4}{x(x+ h)}$
Evaluate limit [Limit Rule - Variable Direct Substitution]: $\displaystyle f'(x) = \frac{4}{x(x+ 0)}$
Simplify: $\displaystyle f'(x) = \frac{4}{x^2}$