What is the slope of the line passing through the points (1,−5) and (4,1)?

In California in 2000, the ballot included an initiative to add "none of the above" to the list of options in all candidate race

sveticcg [70]

Answer:

No, because the sample was randomly selected.

Step-by-step explanation:

In this example, the main element that we need to focus on is the way in which the sample was determined. We learn that the sample was taken in California with 1000 people. However, this sample was random, and the survey was conducted in both English and Spanish. The fact that this was a random sample means that it is representative of the population. The size of the population does not affect the accuracy of a random sample.

4 0

3 years ago

How do you solve 3x+7=x

vredina [299]

3x + 7 = x

First, subtract 3x from both sides. / Your problem should look like: 7 = x - 3x
Second, simplify x - 3x to -2x. / Your problem should look like: 7 = -2x
Third, divide both sides by -2. / Your problem should look like: $\frac{7}{-2}$ = x
Fourth, simplify $\frac{7}{-2}$ to $-\frac{7}{2}$ / Your problem should look like: $- \frac{7}{2}$ = x
Fifth, switch sides. / Your problem should look like: x = $-\frac{7}{2}$

Answer as fraction: $-\frac{7}{2}$
Answer as decimal: -3.5

8 0

3 years ago

Read 2 more answers

Is it true that the planes x + 2y − 2z = 7 and x + 2y − 2z = −5 are two units away from the plane x + 2y − 2z = 1?

zhuklara [117]

Lets Find It Out..

First we'll find the equation of ALL planes parallel to the original one.

As a model consider this lesson:

Equation of a plane parallel to other

The normal vector is:
→n=<1,2−2>

The equation of the plane parallel to the original one passing through P(x0,y0,z0)is:

→n⋅< x−x0,y−y0,z−z0>=0
<1,2,−2>⋅<x−x0,y−y0,z−z0>=0
x−x0+2y−2y0−2z+2z0=0
x+2y−2z−x0−2y0+2z0=0

Or

x+2y−2z+d=0 [1]
where a=1, b=2, c=−2 and d=−x0−2y0+2z0

Now we'll find planes that obey the previous formula and at a distance of 2 units from a point in the original plane. (We should expect 2 results, one for each half-space delimited by the original plane.)
As a model consider this lesson:

Distance between 2 parallel planes

In the original plane let's choose a point.
For instance, when x=0 and y=0:
x+2y−2z=1 => 0+2⋅0−2z=1 => z=−12
→P1(0,0,−12)

In the formula of the distance between a point and a plane (not any plane but a plane parallel to the original one, equation [1] ), keeping D=2, and d as d itself, we get:

D=|ax1+by1+cz1+d|√a2+b2+c2
2=∣∣1⋅0+2⋅0+(−2)⋅(−12)+d∣∣√1+4+4
|d+1|=2⋅3 => |d+1|=6First solution:
d+1=6 => d=5
→x+2y−2z+5=0Second solution:
d+1=−6 => d=−7
→x+2y−2z−7=0

8 0

2 years ago

What does d equal in -24 + 12 (d - 3) + 22

zubka84 [21]

Answer:

-24+12(d-3)+22=-24+34(d-3)

10(d-3)

10d=-30

d=-30/10

d=3

4 0

3 years ago