Every week Avionne gets an allowance of $6.00. Which of the following models illustrates this situation?

FINAL DUE IN 30 MINUTES: the equation 2y + x = 0 is shown on the graph below as a

julia-pushkina [17]

Answer:

Red line

Step-by-step explanation:

2y+x=0

2y=-x

y=-x/2

Put the equation into y=mx+b so you would need to subtract the x to put it on the right side so then you’ll have 2y=-x+0 then divide by 2 to get the y by itself then you’ll have y=-2x+0 that means the line would be negative and the y-intercept is 0 and the only line that follows that is the red line.

6 0

1 year ago

Find the area of the shaded region round to the nearest tenth

Alenkinab [10]

Answer: 818.4

Step-by-step explanation:

Using the area of a sector formula, we get the area of the entire sector is $(\pi)(27.8^{2})\left(\frac{150}{360} \right)$ .

Using the formula $A=\frac{1}{2} ab \sin C$ , we get the area of the triangle is $\frac{1}{2}(27.8)(27.8)(\sin 150^{\circ})$ .

So, the area of the shaded sector is $(\pi)(27.8^{2})\left(\frac{150}{360} \right)-\frac{1}{2}(27.8)(27.8)(\sin 150^{\circ}) \approx \boxed{818.4}$

6 0

1 year ago

Hey I have a question! Here's the question, "Suppose you have a 4-liter bucket and a 7-liter bucket. You need 3 liters of water

prisoha [69]

Fill the 7 litre bucket with water and pour it out into the 4 litre bucket. 3 litres will be left in the 7 litre bucket

8 0

2 years ago

The amount of calories consumed by customers at the Chinese buffet is normally distributed with mean 2617 and standard deviation

Eduardwww [97]

Answer:

a) N(2617, 586)

b) 0.3613 = 36.13% probability that the customer consumes less than 2409 calories.

c) 0.4013 = 40.13% of the customers consume over 2764 calories

d) 3981 calories.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 2617, \sigma = 586$

a. What is the distribution of X?

Here we first place the mean, then the standard deviation.

N(2617, 586)

b. Find the probability that the customer consumes less than 2409 calories.

This is the pvalue of Z when X = 2409. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{2409 - 2617}{586}$

$Z = -0.355$

$Z = -0.355$ has a pvalue of 0.3613

0.3613 = 36.13% probability that the customer consumes less than 2409 calories.

c. What proportion of the customers consume over 2764 calories?

This is 1 subtracted by the pvalue of Z when X = 2764. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{2764 - 2617}{586}$

$Z = 0.25$

$Z = 0.25$ has a pvalue of 0.5987

1 - 0.5987 = 0.4013

0.4013 = 40.13% of the customers consume over 2764 calories

d. The Piggy award will given out to the 1% of customers who consume the most calories. What is the fewest number of calories a person must consume to receive the Piggy award?

Top 1%, so the 100-1 = 99th percentile.

The 99th percentile is the value of X when Z has a pvalue of 0.99. So it is X when Z = 2.327. So

$Z = \frac{X - \mu}{\sigma}$

$2.327 = \frac{X - 2617}{586}$

$X - 2617 = 2.327*586$

$X = 3980.6$

Rounding to the nearest calorie, 3981 calories.

7 0

2 years ago

B Reading Choose the best estimate for the multiplication problem below. 85 x 86

Dmitry_Shevchenko [17]

Answer:

A. 8100

Step-by-step explanation:

85 x 86

To estimate, we multiply 85*100, which is the easiest multiplication, as a multiplication by 100 is the same as placing two zeros at the end of the number.

85*100 = 8500

Since 86 < 100, 85*86 < 8500. Thus, the correct estimate is given by option A.

5 0

2 years ago