Answer:
let's find the gradient first. (m)
Step-by-step explanation:
(10,3) (6,31)
y²-y¹/x²-x¹
31-3/6-3
28/3
(m) =28/3
y-y¹=m(x-x¹)
let's take y¹=3, x¹=10 and m= 28/3
y-3=28/3(x -10)
y-3=(28/3)x -128/3
taking LCM=3
3y-9=28x-128
3y=28x -128+9
3y=28x-119
Soo your equation is:
3y=28x-119
Just replace 'x' in c(x) by d(x)
(cod) (x) = 4(x^2+5x) - 2 = 4x^2 +20x - 2
Thats it!
Answer:
58
Step-by-step explanation:
2-2x-3y5
2-2(2)-3(-4)5
-2+60
58
