Question

If (10,3) and (6,31) are two anchor points on a trend like, then find the equation of the line

Answer 1

Answer:

let's find the gradient first. (m)

Step-by-step explanation:

(10,3) (6,31)

y²-y¹/x²-x¹

31-3/6-3

28/3

(m) =28/3

y-y¹=m(x-x¹)

let's take y¹=3, x¹=10 and m= 28/3

y-3=28/3(x -10)

y-3=(28/3)x -128/3

taking LCM=3

3y-9=28x-128

3y=28x -128+9

3y=28x-119

Soo your equation is:

3y=28x-119