The ratio of carbon-14 to nitrogen-14 in an artifact is 1:7. Given that the half-

A battery can provide a current of 1.80 A at 2.60 V for 6.00 hr. How much energy (in kJ) is produced?A battery can provide a cur

love history [14]

Answer:

The energy which is produced by a battery is 101.1 kJ.

Explanation:

The expression for the energy in terms of voltage, current and time is as follows;

E=VIt

Here, V is the voltage, I is the current and t is the time.

It is given in the problem that a battery can provide a current of 1.80 A at 2.60 V for 6.00 hr.

Calculate the energy of the battery.

E=VIt

Convert time from hour int seconds.

t=6 hr

t=(6)(60)(60)

t=21600 s

Put I= 1.80 A, V= 2.60 V and t= 21600 s in the expression of energy.

E=(2.60)(1.80)(21600)

E= 101.1 kJ

Therefore, the energy which is produced by a battery is 101.1 kJ.

4 0

3 years ago

A statement made prior to an experiment, and based on little scientific evidence, is

Iteru [2.4K]

A- hypothesis
You usually write hypothesis in science it’s something that can usually be tested.

B- prediction
Made before you do an science experiment, they’re usually like what you think could happen or will happen.

C- theory
Theses aren’t used with scientific evidence, they’re usually things that people believe happened. Example: Some believe Big Foot is real. But no one will ever know because its a theory

D- is already been eliminated, not all are right.

Answer is A

Hope this helped :)

7 0

4 years ago

A 100 kg box as showsn above is being pulled along the x axis by a student. the box slides across a rough surface, and its posit

Anit [1.1K]

Answer:

a) 2 m/s

b) i) $K.E = 50 (1.5t^2 + 2) ^2\\$

ii) $F = 3tm$

Explanation:

The function for distance is $x = 0.5t ^3 + 2t$

We know that:

Velocity = $v= \frac{d}{dt} x$

Acceleration = $a= \frac{d}{dt}v$

To find speed at time t = 0, we derivate the distance function:

$x = 0.5 t^3 + 2t\\v= x' = 1.5t^2 + 2$

Substitute t = 0 in velocity function:

$v = 1.5t^2 + 2\\v(0) = 1.5 (0) + 2\\v(0) = 2$

Velocity at t = 0 will be 2 m/s.

To find the function for Kinetic Energy of the box at any time, t.

$Kinetic \ Energy = \frac{1}{2} mv^2\\\\K.E = \frac{1}{2} \times 100 \times (1.5t^2 + 2) ^2\\\\K.E = 50 (1.5t^2 + 2) ^2\\$

We know that $Force = mass \times acceleration$

$a = v'(t) = 1.5t^2 + 2\\a = 3t$

$F = m \times a\\F= m \times 3t\\F = 3tm$

6 0

4 years ago

TRUE OR FALSE. when an object changed direction without changing its speed, it is not accelerating

tatyana61 [14]

Answer:

True.

Explanation:

The velocity vector is constant in magnitude but changing in direction. Because the speed is constant for such a motion, many students have the misconception that there is no acceleration. ... But the fact is that an accelerating object is an object that is changing its velocity.

3 0

3 years ago

A 0.5-kilogram ball is thrown vertically upward with an initial kinetic energy of 25 joules. Ap-proximately how high will the ba

tatuchka [14]

It's gravitational potential energy at the top will roughly equal it's kinetic energy when it was released (a little is lost to air resistance). Note this will assume the release point is zero potential energy. (we are free to define it that way, just letting you know). Gravitational potential energy is mgh.
mgh=25J
h=25J/(0.5kg x 9.81m/s^2) = 5.097m
So it goes about 5.1 meters above the point where it was released

4 0

3 years ago