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liq [111]
3 years ago
14

]What is a GOOD AND DETAILED conclusion on a thermos. will be awarded 15 points im desperate

Physics
1 answer:
nordsb [41]3 years ago
8 0
In conclusion, a thermos is a useful drinking cup for storing hot liquids in certain room temperatures. Drinks like coffee, tea, and other hot liquids can still stay warm thanks to the thermos.
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A student is examining a bacterium under the microscope. The E. coli bacterial cell has a mass of m = 0.900 fg (where a femtogra
just olya [345]

Answer:

9.73 x 10⁻¹⁰ m

Explanation:

According to Heisenberg uncertainty principle

Uncertainty in position x uncertainty in momentum ≥ h / 4π

Δ X x Δp ≥ h / 4π

Δp = mΔV

ΔV = Uncertainty in velocity

= 2 x 10⁻⁶ x 3 / 100

= 6 x 10⁻⁸

mass m = 0.9 x 10⁻¹⁵ x 10⁻³ kg

m = 9 x 10⁻¹⁹

Δp = mΔV

= 9 x 10⁻¹⁹ x 6 x 10⁻⁸

= 54 x 10⁻²⁷

Δ X x Δp ≥ h / 4π

Δ X x  54 x 10⁻²⁷ ≥ h / 4π

Δ X = h / 4π x 1 /  54 x 10⁻²⁷

= \frac{6.6\times10^{-34}}{4\times3.14\times54\times10^{-27}}

= 9.73 x 10⁻¹⁰ m

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3 years ago
What do folds on a strip of paper mean
Vlad [161]
There are creases. Or just origami
7 0
2 years ago
What is the relationship between DNA and mutation
Scrat [10]

Answer:

A mutation is a change in DNA, the hereditary material of life. An organism's DNA affects how it looks, how it behaves, and its physiology. So a change in an organism's DNA can cause changes in all aspects of its life. Mutations are essential to evolution; they are the raw material of genetic variation

Explanation:

5 0
2 years ago
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A person's body is producing energy internally due to metabolic processes. If the body loses more energy than metabolic processe
Allushta [10]

To solve this problem it is necessary to apply the concepts related to the Stefan-Boltzman law that is responsible for calculating radioactive energy.

Mathematically this expression can be given as

P = \sigma Ae\Delta T^4

Where

A = Surface area of the Object

\sigma = Stefan-Boltzmann constant

e = Emissivity

T = Temperature (Kelvin)

Our values are given as

A = 1.36m^2

\Delta T^4 = T_2^4 -T_1^4 = 307^4-T_1^4

\sigma = 5.67*10^{-8} J/(s m^2 K^4)

P = 122J/s

e = 0.7

Replacing at our equation and solving to find the temperature 1 we have,

P = \sigma Ae\Delta T^4

P = \sigma Ae (T_2^4 -T_1^4)

122 = (5.67*10^{-8})(1.36)(0.7)(307^4-T_1^4)

T_1 = 285.272K = 12.122\°C

Therefore the the temperature of the coldest room in which this person could stand and not experience a drop in body temperature is 12°C

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3 years ago
Plz! How to solve this question? The answer is B.
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