Answer:
21.6 kN
Explanation:
F = m * a
F = 54 000 * .4 = 21600 N
Answer:
The resistivity of the wire is 
Explanation:
We have,
Length of a wire is 40 cm or 0.4 m
Diameter of a wire is 0.60 mm
Radius is 0.3 mm or 0.0003 m
Resistance of a wire is 1.5 ohm
Now we need to find the resistivity of the material of which it is made. The resistance of a wire in terms of its resistance, length and area is given by :
= resistivity
So, the resistivity of the wire is .
<span>The electric force is given by:
F = [ k*(q1)*(q2) ] / d^2
F = Electric force
k = Coulomb's constant
q1 = Charge of one proton
q2 = Charge of second proton
d = Distance between centers of mass
Values:
F = unknown
k = 8.98E 9 N-m^2/C^2
q1 = 1.6E-19
q2 = 1.6E-19
d = 1.0E-15 m
Insert values into F = [ k*(q1)*(q2) ] / d^2
F = [ (8.98E 9 N-m^2/C^2) * (1.6E-19) * (1.6E-19) ] / (1.0E-15 m)^2
F = </span>229.888 N
answer
the electric force of repulsion between nuclear protons is 229.888 N
Average speed =
(distance covered during some period of time)
divided by
(length of time to cover that distance).
