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Anastasy [175]
3 years ago
15

10 points

Physics
1 answer:
enot [183]3 years ago
8 0

Answer:

B

Explanation:

I just took the test

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Consider two celestial objects with masses m1 and m2 with a separation distance between their centers r. If the first mass m1 we
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The new magnitude of the force of attraction will be 6 times the original force of attraction

<h3>How to determine the initial force </h3>
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  • Mass 2 = m₂
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  • Distance apart = r
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F = Gm₁m₂ / r²

F₁ = Gm₁m₂ / r²

<h3>How to determine the new force </h3>
  • Mass 1 = 2m₁
  • Mass 2 = 3m₂
  • Gravitational constant = G
  • Distance apart (r) = r
  • New force (F₂) =?

F = Gm₁m₂ / r²

F₂ = G × 2m₁ × 3m₂ / r²

F₂ = 6Gm₁m₂ / r²

But

F₁ = Gm₁m₂ / r²

Therefore

F₂ = 6Gm₁m₂ / r²

F₂ = 6F₁

Thus, the new magnitude of the force of attraction will be 6 times the original force of attraction

Learn more about gravitational force:

brainly.com/question/21500344

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