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3 years ago

What is the volume of a hemisphere with a diameter of 45.7 m, rounded to the nearest tenth of a cubic meter?

Mathematics

1 answer:

worty [1.4K]3 years ago

6 0

24987.2 meters cubed.

Step-by-step explanation:

A Hemisphere is 1/2 of a sphere, so let's find the volume of a sphere and then cut it in half.

The volume of a sphere is V= (4/3)πr3

The diameter is double the size of the radius, so we can find r, the radius, by dividing the diameter,

45.7m, by 2. So r = 22.85 meters

so the volume of the sphere is (4/3)π(22.85 meters)3, which is 49974.35787 meters cubed.

Since we're actually looking for the Hemisphere, we can divide this volume in half to get the volume of the hemisphere as 24987.17894 meters cubed.

And because the answer must be to 1/10th of a cubic meter, that means we only want one decimal point. So we round to 24987.2 meters cubed.

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Let us remove parenthesis.

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Since $5g+(-5g)$ simplifies to 0, therefore, expression $5g+(-5g)$ is a correct choice.

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Let us combine the terms as:

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4 years ago

Read 2 more answers