Most events in track and field are individual except relay races. Therefore, it would probably be true.
The magnitude of the electric field for the bead to hang suspended in air is 9.19×10⁵V/m and the field is directed downwards.
If <em>n</em> electrons each of charge <em>e</em> are added to the bead, the total charge <em>q</em> on the bead is given by
Substitute 1.0×10¹⁰ for n and 1.6×10⁻¹⁹C for e.
The bead ha a negative charge of magnitude 1.6×10⁻⁹C.
The bead has a mass m and its weight mg is directed downwards. The bead can be balanced in an electric field of strength E if the force it experiences due to the electric field is directed upwards and is equal to the magnitude of its weight. This is shown in the diagram attached.
For equilibrium,
Rewrite the expression for E.
Substitute 0.15 g = 0.15×10⁻³kg for m, 9.8 m/s² for g and 1.6×10⁻⁹C for q.
The magnitude of the electric field required to balance the bead is <u>9.19×10⁵V/m.</u>
The bead is negatively charged. For the bead to experience a force in the upward direction, the electric field is to be directed down wards.
The electric field is directed downwards.
Answer: 49.4g
Explanation:
Weight = 484N
Mass = ?
Recall that the weight of an object is a product of its mass (m) by gravitational acceleration (g). And g is a constant with value of 9.8 ms2
Thus, Weight = mg
484N = mass x 9.8 ms2
Mass = (484/9.8)
Mass = 49.388g
(Rounded to the nearest tenth, the mass becomes 49.4g)
Thus, your father is 49.4grams in mass
Answer:
a) , b) , c) , d)
Explanation:
b) The kinetic energy for a rigid body is the sum of translational and rotational kinetic energy:
The speed of the center of mass of the sphere at the initial position is:
a) The kinetic energy associated with the rotation is:
It is 40 % of the total initial kinetic energy.
c) The total final kinetic energy is:
d) The speed of its center of mass is: