To solve this problem it is necessary to apply the definition given in Faraday's law in a solenoid for which it is noted that
![\epsilon = - d\frac{\phi_B}{dt}](https://tex.z-dn.net/?f=%5Cepsilon%20%3D%20-%20d%5Cfrac%7B%5Cphi_B%7D%7Bdt%7D)
![\epsilon = -NA\frac{dB}{dt}](https://tex.z-dn.net/?f=%5Cepsilon%20%3D%20-NA%5Cfrac%7BdB%7D%7Bdt%7D)
Where,
N = Number of loops
A = Cross sectional Area
B = Magnetic Field
![\epsilon = (15)(\pi(0.03)^2)\frac{0-0.5}{0.1}](https://tex.z-dn.net/?f=%5Cepsilon%20%3D%20%2815%29%28%5Cpi%280.03%29%5E2%29%5Cfrac%7B0-0.5%7D%7B0.1%7D)
![\epsilon = 0.212V](https://tex.z-dn.net/?f=%5Cepsilon%20%3D%200.212V)
![\epsilon = 0.21V](https://tex.z-dn.net/?f=%5Cepsilon%20%3D%200.21V)
Therefore the correct answer is A.
Answer: The correct answer is B
Explanation: The string is pulling right and the string is unraveling causing it to accelerate left
Answer:
Area = 20 m²
Explanation:
Given the following data;
Force = 2500 N
Pressure = 125 Pa
To find the area on which it rest;
Mathematically, pressure is given by the formula;
![Pressure = \frac {Force}{area}](https://tex.z-dn.net/?f=%20Pressure%20%3D%20%5Cfrac%20%7BForce%7D%7Barea%7D%20)
Making area the subject of formula, we have;
![Area = \frac {Force}{pressure}](https://tex.z-dn.net/?f=%20Area%20%3D%20%5Cfrac%20%7BForce%7D%7Bpressure%7D%20)
Substituting into the formula, we have;
![Area = \frac {2500}{125}](https://tex.z-dn.net/?f=%20Area%20%3D%20%5Cfrac%20%7B2500%7D%7B125%7D%20)
Area = 20 m²
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