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Anuta_ua [19.1K]
3 years ago
11

The efficiency of a machine increases as the temperature inside _____ relative to the temperature outside.

Physics
2 answers:
Paha777 [63]3 years ago
8 0
It is increases that is the answer

Archy [21]3 years ago
5 0
The answer is increases
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Enter the expression
vlabodo [156]
I see the word "when..." kind of fading out at the end of the first line.
Whatever comes after it may be important.

If you're just supposed to copy the expression into the box,
then the problem is that you left the 'e' out of it.

I'm guessing that you're supposed to enter whatever the expression becomes
when either  N₀ or  ' t ' has some special value that's in the first line.

Just taking a wild guess here . . . . .

If it's  "Enter the expression ..... , when t=0 ." ,
then the correct answer in the box is     N₀  .

But that's just a wild guess.  As I pointed out, you cut off
the picture in the middle of the word 'when', and I've got
a hunch that there's something important after it.
6 0
3 years ago
The 8 kg block is then released and accelerates to the right, toward the 2 kg block. The surface is rough and the coefficient of
natita [175]

Answer:

3.258 m/s

Explanation:

k = Spring constant = 263 N/m (Assumed, as it is not given)

x = Displacement of spring = 0.7 m (Assumed, as it is not given)

\mu = Coefficient of friction = 0.4

Energy stored in spring is given by

U=\dfrac{1}{2}kx^2\\\Rightarrow U=\dfrac{1}{2}\times 263\times 0.7^2\\\Rightarrow U=64.435\ J

As the energy in the system is conserved we have

\dfrac{1}{2}mv^2=U-\mu mgx\\\Rightarrow v=\sqrt{2\dfrac{U-\mu mgx}{m}}\\\Rightarrow v=\sqrt{2\dfrac{64.435-0.4\times 8\times 9.81\times 0.7}{8}}\\\Rightarrow v=3.258\ m/s

The speed of the 8 kg block just before collision is 3.258 m/s

7 0
3 years ago
I need the answer for both of the questions please
Lady_Fox [76]
But even more pain on pain and then pain and pain ya feel me and even more pain okay and yes more pain
5 0
3 years ago
object P1 and P2 are in a straight line with the normal to a plane mirror.If P1 and P2 are 18m and 21m away from the mirror. Cal
VARVARA [1.3K]

The distance between object P1 and its image formed is determined as 36 m.

<h3>Distance of the image</h3>

The distance of the image formed by object P1 is calculated as follows;

In a plane mirror; object distance = image distance

image distance of P1 = 18 m

distance between object and image = 18m + 18 m = 36 m

Thus, the distance between object P1 and its image formed is determined as 36 m.

Learn more about plane mirrors here: brainly.com/question/1126858

#SPJ1

8 0
2 years ago
During a solar eclipse, which of the following is true?
kaheart [24]

Answer:

The Moon blocks the suns light from hitting the surface of the earth

6 0
3 years ago
Read 2 more answers
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