The fastest propeller-driven aircraft is the Russian TU-95/142, which canreach a maximum speed of 925 km/h. For this speed, calc
ulate the plane'sresultant displacement if it travels east for 1.50 h, then turns 135° north-west and travels for 2.00 h
1 answer:
Answer:
The resultant displacement of plane = 1310.76 Km
Explanation:
Given that,
Speed of the plane = 925 Km/h
Therefore, in 1 hour plane travels 925 Km
From figure,
Displacement if it travels east for 1.5 h, AB = 1387.5 Km
Displacement if it travels north-west for 2 h, BC = 1850 Km
Angle formed between two displacement = 135°
The resultant displacement is given by the relation
AC² = AB² + BC² + 2 AB BC Cos θ
Substituting the values in the equations,
AC² = 1387.5² + 1850² + 2 x 1387.5 x 1850 x Cos 135°
= 1718095
AC = 1310.76
Therefore, the resultant displacement of plane is 1310.76 Km
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