The fastest propeller-driven aircraft is the Russian TU-95/142, which canreach a maximum speed of 925 km/h. For this speed, calc
ulate the plane'sresultant displacement if it travels east for 1.50 h, then turns 135° north-west and travels for 2.00 h
1 answer:
Answer:
The resultant displacement of plane = 1310.76 Km
Explanation:
Given that,
Speed of the plane = 925 Km/h
Therefore, in 1 hour plane travels 925 Km
From figure,
Displacement if it travels east for 1.5 h, AB = 1387.5 Km
Displacement if it travels north-west for 2 h, BC = 1850 Km
Angle formed between two displacement = 135°
The resultant displacement is given by the relation
AC² = AB² + BC² + 2 AB BC Cos θ
Substituting the values in the equations,
AC² = 1387.5² + 1850² + 2 x 1387.5 x 1850 x Cos 135°
= 1718095
AC = 1310.76
Therefore, the resultant displacement of plane is 1310.76 Km
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Answer:
i) FALSE, ii) TRUE, iii) FALSE, iv) FALSE
Explanation:
When light (electromagnetic radiation) travels through a material medium, its speed is less than the speed of light in a vacuum. If we define the index of parts
n = c / v
where v is the speed of light in the material medium.
The direction of the ray can be determined by the law of refraction
n₁ sin θ₁ = n₂ sin θ₂
Let's apply these equations to our case where
nₓ <n_y
i) The expression of the refractive index
nₓ < n_y
v_y <vₓ
therefore the expression is FALSE
ii) If we use the law of refraction, the light, when passing from a medium with a lower start to another with a higher index, must approach the normal one, away from what would be the continuation of the path of the incident ray
so the expression is TRUE
iii) The speed of light is constant in all material media
the statement is FALSE
iv) light approaches normal
Let me clarify that the normal is a line perpendicular to the surface at the point of contact, not the direction of Io.
the statement of FALSE
Answer:
α = 1930.2 rad/s²
Explanation:
The angular acceleration can be found by using the third equation of motion:
where,
α = angular acceleration = ?
θ = angular displacement = (1500 rev)(2π rad/1 rev) = 9424.78 rad
ωf = final angular speed = 0 rad/s
ωi = initial angular speed = (960 rev/s)(2π rad/1 rev) = 6031.87 rad/s
Therefore,
<u>α = - 1930.2 rad/s²</u>
<u>negative sign shows deceleration</u>