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bekas [8.4K]
3 years ago
12

The fastest propeller-driven aircraft is the Russian TU-95/142, which canreach a maximum speed of 925 km/h. For this speed, calc

ulate the plane'sresultant displacement if it travels east for 1.50 h, then turns 135° north-west and travels for 2.00 h

Physics
1 answer:
valentinak56 [21]3 years ago
7 0

Answer:

The resultant displacement of plane = 1310.76 Km

Explanation:

Given that,

Speed of the plane = 925 Km/h

Therefore, in 1 hour plane travels 925 Km

From figure,

Displacement if it travels east for 1.5 h, AB = 1387.5 Km

Displacement if it travels north-west for 2 h, BC = 1850 Km

Angle formed between two displacement = 135°

The resultant displacement is given by the relation

          AC² = AB² + BC² + 2 AB BC Cos θ

Substituting the values in the equations,

           AC²  = 1387.5² + 1850² + 2 x 1387.5 x 1850 x Cos 135°

                    = 1718095

           AC =  1310.76

Therefore, the resultant displacement of plane is 1310.76 Km

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Sunshine Corporation is expected to pay a dividend of $1.50 in the upcoming year. Dividends are expected to grow at the rate of
grigory [225]

Answer:

$25

Explanation:

The computation of the intrinsic value of the stock is shown below:

As we know that

Intrinsic value or Price = Dividend ÷ (Cost of equity - growth rate)

where,

Cost of equity or ke  is

= Risk free rate of return  + beta × (Market rate of return - risk free rate of return)

= 6% + 0.75 × (14% - 6%)

= 12 %

So the intrinsic value is

= $1.50 ÷ (12% - 6%)

= $25

7 0
3 years ago
Read 2 more answers
if a current of 0.3 ampere flows through a conductor of resistance of 11.7 ohm's,the voltage across the ends of the conductor is
Gnesinka [82]

Here,

Resistance = 11.7

Ampere = 0.3

Voltage = ?

Now,

R = V/A

11.7 = V/0.3

11.7*0.3 =V

V = 3.51

I hope it's help you...

Mark me as brainliest...

7 0
3 years ago
Find the magnitude of the free-fall acceleration at the orbit of the Moon (a distance of 60RE from the center of the Earth with
Ede4ka [16]

Answer:

The magnitude of the free-fall acceleration at the orbit of the Moon is 2.728\times 10^{-3}\,\frac{m}{s^{2}} (\frac{2.784}{10000}\cdot g, where g = 9.8\,\frac{m}{s^{2}}).

Explanation:

According to the Newton's Law of Gravitation, free fall acceleration (g), in meters per square second, is directly proportional to the mass of the Earth (M), in kilograms, and inversely proportional to the distance from the center of the Earth (r), in meters:

g = \frac{G\cdot M}{r^{2}} (1)

Where:

G - Gravitational constant, in cubic meters per kilogram-square second.

M - Mass of the Earth, in kilograms.

r - Distance from the center of the Earth, in meters.

If we know that G = 6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}}, M = 5.972\times 10^{24}\,kg and r = 382.26\times 10^{6}\,m, then the free-fall acceleration at the orbit of the Moon is:

g = \frac{\left(6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}} \right)\cdot (5.972\times 10^{24}\,kg)}{(382.26\times 10^{6}\,m)^{2}}

g = 2.728\times 10^{-3}\,\frac{m}{s^{2}}

6 0
3 years ago
A certain kind of glass has an index of refraction of 1.640 for blue light of wavelength 440 nm and an index of 1.595 for red li
seraphim [82]

Answer: 18.27°

Explanation:

Given

Index of refraction of blue light, n(b) = 1.64

Wavelength of blue light, λ(b) = 440 nm

Index of refraction of red light, n(r) = 1.595

Wavelength of red light, λ(r) = 670 nm

Angle of incident, θ = 30°

Angle of refraction of red light is

θ(r) = sin^-1 [(n(a)* sin θ) / n(r)], where n(a) = index of refraction of air = 1

So that,

θ(r) = sin^-1 [(1 * sin 30) / 1.595]

θ(r) = sin^-1 (0.5 / 1.595)

θ(r) = sin^-1 0.3135

θ(r) = 18.27°

4 0
3 years ago
What is the voltage in a circuit that has a current of 10.0 amps and a resistance of 28.5 ohms?
marin [14]
Voltage = Current (I) × Resistance (R)
V = 10 × 28.5 = 285v
6 0
3 years ago
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