Question

The fastest propeller-driven aircraft is the Russian TU-95/142, which canreach a maximum speed of 925 km/h. For this speed, calculate the plane'sresultant displacement if it travels east for 1.50 h, then turns 135° north-west and travels for 2.00 h

Answer 1

Answer:

The resultant displacement of plane = 1310.76 Km

Explanation:

Given that,

Speed of the plane = 925 Km/h

Therefore, in 1 hour plane travels 925 Km

From figure,

Displacement if it travels east for 1.5 h, AB = 1387.5 Km

Displacement if it travels north-west for 2 h, BC = 1850 Km

Angle formed between two displacement = 135°

The resultant displacement is given by the relation

          AC² = AB² + BC² + 2 AB BC Cos θ

Substituting the values in the equations,

           AC²  = 1387.5² + 1850² + 2 x 1387.5 x 1850 x Cos 135°

                    = 1718095

           AC =  1310.76

Therefore, the resultant displacement of plane is 1310.76 Km