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Trava [24]
3 years ago
5

The function c=180n+250 represents the total lodging cost c (in dollars) for a stay at a vacation destination of n nights.

Mathematics
1 answer:
Svetlanka [38]3 years ago
8 0

Given:

The function for the total lodging cost c (in dollars) for a stay at a vacation destination of n nights is

c=180n+250

Budget = $900

To find:

The number of nights you can stay at you vacation destination.

Solution:

Since, budget is $900, therefore, the cost must be less than or equal to $900.

c\leq 900

180n+250\leq 900

180n\leq 900-250

180n\leq 650

Divide both sides by 180.

n\leq \dfrac{650}{180}

n\leq 3.611

Number of nights must be a whole number. So, greatest whole value of n is 3.

Therefore, you can stay 3 nights, i.e., n=3.

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Determine the vertical asymptotes and holes for the graph of the equation below.
Lapatulllka [165]

Since <em>x</em> ² + 8<em>x</em> + 7 = (<em>x</em> + 7) (<em>x</em> + 1), we have for <em>x</em> ≠ -7,

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Which is the graph of y= 2(x-3)^2 +2
WINSTONCH [101]

The graph of y = 2(x - 3)² + 2 can be seen in the attached picture. This problem can be solved through the concept of parabola and transformation.

<h3>Further explanation</h3>

<u>The Problem:</u>

Which is the graph of y = 2(x - 3)² + 2?

<u>Question-1:</u>

How to make a graph y = 2 (x - 3) ² + 2 through the concept of a parabola.

<u>The Process:</u>

The equation of a parabola is given by \boxed{ \ y = a(x - h)^2 + k \ }.

Keep in mind the following points:

  • vertex point at (h, k)
  • axis of symmetry at x = h
  • a > 0 the parabola opens upward
  • a < 0 the parabola opens downward
  • the y-intercept is \boxed{ \ y = ah^2 + k \ } at x = 0.

From our case it can be concluded as follows:

  • the graph of y = 2(x - 3)² + 2 opens upward
  • vertex point at (3, 2)
  • axis of symmetry at x = 3
  • the y-intercept is 2(3²) + 2 = 20 or in coordinates of (0, 20)

<u>Question-2:</u>

How to make the graph of y = 2(x - 3)² + 2 through the transformation.

<u>The Process:</u>

To plot the graph of y = 2(x - 3) ² + 2 we apply for the following transformation order:

Step-1: clearly, to obtain the graph of y = (x - 3)² we shift the graph of y = x² to the right 3 units.

Step-2: to obtain the graph of y = 2(x - 3)², we stretch the graph of y = (x - 3)²  by a factor of 2 (in other words, multiply each y-coordinate by 2).

Step-3: finally, to obtain the graph of y = 2(x - 3)² + 2 we shift the graph of y = 2(x - 3)² upward 3 units.

Thus the construction of the graph y = 2 (x - 3) ² + 2 is completed.

The graph of y = 2(x - 3) ² + 2 is drawn by the combination of shifting the graph of y = x² to the right 3 units and upward 2 units, and also stretch by a factor of 2. Between vertical shift and stretch steps, it is the same whatever steps are taken first.

- - - - - - - - - -

Notes

  • The transformation of graphs is changing the shape and location of a graph.  
  • There are four types of transformation geometry: translation (or shifting), reflection, rotation, and dilation (or stretching/shrinking).  
  • In this case, the transformation is shifting horizontally and vertically and also stretching vertically.

In general, given the graph of y = f(x) and v > 0, we obtain the graph of:  

  • \boxed{ \ y = f(x) + v \ } by shifting the graph of \boxed{ \ y = f(x) \ } upward v units.  
  • \boxed{ \ y = f(x) - v \ } by shifting the graph of \boxed{ \ y = f(x) \ } downward v units.  

That's the vertical shift, now the horizontal one. Given the graph of y = f(x) and h > 0, we obtain the graph of:  

  • \boxed{ \ y = f(x + h) \ } by shifting the graph of \boxed{ \ y = f(x) \ } to the left h units.  
  • \boxed{ \ y = f(x - h) \ } by shifting the graph of \boxed{ \ y = f(x) \ } to the right h units.

Hence, the combination of vertical and horizontal shifts is as follows:  

\boxed{ \ y = f(x \pm h) \pm v \ }  

The plus or minus sign follows the direction of the shift, i.e., up-down or left-right .

Notice the following definitions for stretch and shrink.

  • In general, given the graph of \boxed{y = f(x)}, we obtain the graph of \boxed{y = cf(x)} by stretching \boxed{ \ c > 1 \ } or shrinking \boxed{ \ 0 < c < 1 \ } the graph of \boxed{y = f(x)} vertically by a factor of c.
  • In general, given the graph of \boxed{y = f(x)}, we obtain the graph of \boxed{y = f(cx)} by stretching \boxed{ \ 0 < c < 1 \ } or shrinking \boxed{ \ c > 1 \ } the graph of \boxed{y = f(x)} horizontally by a factor of c.
<h3>Learn more  </h3>
  1. What is the y-intercept of the quadratic function  f(x) = (x – 6)(x – 2)? brainly.com/question/1332667
  2. Transformations that change the graph of (f)x to the graph of g(x) brainly.com/question/2415963
  3. Which statement correctly describes the graph  brainly.com/question/10929552

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marissa [1.9K]

Answer:

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Step-by-step explanation:

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So

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0 > -2 : NO  (solutions will be any values less than -2)

3 > -2 : NO  (solutions will be any values less than -2)

Answer

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aleksandrvk [35]

Answer:

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Step-by-step explanation:

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on the second attempt;

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on the third attempt;

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on the fourth attempt;

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so we add everything;  

⇒ 10/39 + 14/143 + 35/1287 + 5/1287

= 0.38539

Therefore, the probability that Jack draws the blue ball is 0.38539

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