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olga55 [171]
3 years ago
6

Need help please thanks

Mathematics
1 answer:
Ivahew [28]3 years ago
5 0

Answer:

A

Step-by-step explanation:

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A pharmacist receives a shipment of 21 bottles of a drug and has three of the bottles tested. If five of the 21 bottles are cont
blagie [28]

Answer:

The probability is 0.8722

Step-by-step explanation:

There are 21 bottles

5 of them are contaminated.

there are 21 - 5 = 16 non-contaminated bottles.

So, if we grab a bottle at random, the probability that this bottle is contaminated will be equal to the quotient between the number of contaminated bottles and the total number of bottles, this is:

p = 5/21

Now we want to find the probability that, for 3 tested bottles, that less than two (0 or 1 ) are contaminated.

Let's see each case on its own.

0 bottles:

The probability of getting a non-contaminated bottle in the first try is equal to the quotient between the number of non-contaminated bottles and the total number of bottles, this is:

p₁ = 16/21

For the second bottle is the same, but because one non-contaminated bottle was drawn before, now there are 15 non-contaminated bottles and 20 bottles in total, so now the probability is:

p₂ = 15/20

and similarly, for the third bottle the probability is:

p₃ = 14/19

The joint probability is the product of the individual probabilities, we get:

P = p₁*p₂*p₃ = (16/21)*(15/20)*(14/19) = 0.4211

Now the case that one bottle is contaminated.

Let's assume that the first one is contaminated.

The probability of getting a contaminated bottle in the first draw is equal to the quotient between the number of contaminated bottles and the total number of bottles, so:

p₁ = 5/21

For the second bottle, we want a non-contaminated one, there are 16 non-contaminated bottles and 20 bottles left, so here the probability is:

p₂ = 16/20

and for the third bottle we have the probability:

p₃ = 15/19

The joint probability is:

p = p₁*p₂*p₃ = (5/21)*(16/20)*(15/19)

Also notice that we only looked at the case where the first bottle is contaminated, we also have the case where the second one is contaminated and the case where the third one is  contaminated, so there are 3 permutations, then the probability of having one contaminated bottle is:

Q = 3*p = 3*(5/21)*(16/20)*(15/19) = 0.4511

Then the probability of having less than two contaminated bottles is:

probability = P + Q = 0.4211 + 0.4511 = 0.8722

8 0
3 years ago
Plzzzzz help i'm in desprate need of help with this
Ainat [17]

Answer:

Obtuse

Step-by-step explanation:

Right = has angle measure of 90°

Acute = has angle measure less than 90°

Equilateral = 2 or more angles whose angle measures are congruent to others

Circle = measures 360°

<u>Obtuse = Angle measure greater than 90° and less than 180°</u>

Hope this helps!

5 0
3 years ago
I need help it’s hard please help
mel-nik [20]
Woohoo
okay, so is z less than or grater than 2/5? greater so you would just label your graph then where ever you put 2/5 you put all the other dots or an arrow going to the right but put an open circle then the arrow something like this
o------------>
(2/5--------->)
sorry if confusing
6 0
3 years ago
Item cost 3.60 a bottle and there are 6 in each case how much would 4 cases cost
Vlad [161]
So there's 6 bottles and each bottle costs 3.60 but there's 4 cases.

So first multiply the number of bottles which is 6 with the cases which is 4.

6 x 4 = 24,so there's 24 bottles.Now multiply the price of the bottles time 24.

24 x 3.60 = 86.4.So the person that bought that will have to pay 86.4.Man those things are expensive.

Hope this helps :D
7 0
3 years ago
Luna entered a raffle for a new pair of running shoes. She purchased 20 tickets and was told that she had a 20%
ValentinkaMS [17]

Answer:

She had to sell 4 tickets

Step-by-step explanation:

Do 20 times 20%

20% OF 20

5 0
4 years ago
Read 2 more answers
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