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satela [25.4K]
3 years ago
15

Im pretty sure i asked the same question twice sorry lol

Physics
1 answer:
Aliun [14]3 years ago
3 0
Lmbo me tryna get some free points
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78 grams of a radioactive nuclei X undergoes radioactive decay. The half-life of X is 4.7 minutes. After 16.5 minutes, the remai
kipiarov [429]

<u>Answer:</u> The remaining sample of X is 6.9 grams.

<u>Explanation:</u>

All the radioactive reactions follow first order kinetics.

The equation used to calculate rate constant from given half life for first order kinetics:

t_{1/2}=\frac{0.693}{k}

We are given:

t_{1/2}=4.7min

Putting values in above equation, we get:

k=\frac{0.693}{4.7min}=0.147min^{-1}

The equation used to calculate time period follows:

N=N_o\times e^{-k\times t}

where,

N_o = initial mass of sample X = 78 g

N = remaining mass of sample X = ? g

t = time = 16.5 min

k = rate constant = 0.147min^{-1}

Putting values in above equation, we get:

N=78\times e^{-(0.147min^{-1}\times 16.5min)}\\\\N=6.9g

Hence, the remaining amount of sample X is 6.9 g

4 0
4 years ago
A 1,550 kg car moving south at 10.0 m/s collides with a 2,550 kg car moving north. The cars stick together and move as a unit af
nikitadnepr [17]

Answer:

14.47 m/s

Explanation:

The momentum must be preserved before and after the collision:

The total momentum before the collision

m_1v_1 + m_2v_2

where m_1 = 1550 kg, m_2 = 2550 kg are the masses of the car moving south and north, respectively, before the collision. v_1 = -10m/s is the velocity of the car moving South. We take the velocity to the North as the positive direction

The total momentum after the collision

(m_1 + m_2)V

where V = 5.22m/s is the velocity of both cars after the collision

We can equalize the 2 equations and plug in the numbers:

m_1v_1 + m_2v_2 = (m_1 + m_2)V

1550(-10) + 2550*v_2 = (1550 + 2550)5.22

-15500 + 2550v_2 = 21402

2550v_2 = 36902

v_2 = 36902/2550 = 14.47 m/s

6 0
3 years ago
Which two energy sources can help a star maintain its internal thermal pressure? which two energy sources can help a star mainta
Lapatulllka [165]
Nuclear fusion and gravitational contraction

<span>constituent of star is hydrogen(including isotope) or helium. nuclear fission is almost impossible. D(deuterium; isotope of hydrogen) and T(tritium; also isotope of hydrogen) reacts and helium is formed. During this reaction, severe energy is generated. Heavier elements are formed and pulls each other. Gathered elements forms core of star. Gravity of the core prevents the gas to run away.</span>
8 0
4 years ago
Read 2 more answers
Understanding how behavior has changed over time to help humans adapt to their environment is known as the __________ approach t
Lostsunrise [7]
I believe the behavioral
6 0
3 years ago
In a perfectly inelastic collision, the total momentum of the system ___(i)___ constant, while the total kinetic energy of the s
Olegator [25]

Answer:

(i) Momentum of the system is constant

(ii) Total kinetic energy of the system is not constant.

Explanation:

In perfectly inelastic collision, the total momentum of the system is constant while the the total kinetic energy of the system is not constant. The total; kinetic energy is not constant because some of the energy is lost in the process of collision. In this case, two bodies sticks together and both will move with a constant velocity. Also, the coefficient of restitution is equal to 0.

3 0
4 years ago
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