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aleksandrvk [35]
4 years ago
7

Which two energy sources can help a star maintain its internal thermal pressure? which two energy sources can help a star mainta

in its internal thermal pressure? nuclear fission and gravitational contraction nuclear fusion and chemical reactions chemical reactions and gravitational contraction nuclear fusion and gravitational contraction nuclear fusion and nuclear fission?
Physics
2 answers:
Lapatulllka [165]4 years ago
8 0
Nuclear fusion and gravitational contraction

<span>constituent of star is hydrogen(including isotope) or helium. nuclear fission is almost impossible. D(deuterium; isotope of hydrogen) and T(tritium; also isotope of hydrogen) reacts and helium is formed. During this reaction, severe energy is generated. Heavier elements are formed and pulls each other. Gathered elements forms core of star. Gravity of the core prevents the gas to run away.</span>
liberstina [14]4 years ago
5 0

Answer:

nuclear fission and gravitational contraction

Explanation:

Which two energy sources can help a star maintain its internal thermal pressure? which two energy sources can help a star maintain its internal thermal pressure? nuclear fission and gravitational contraction nuclear fusion and chemical reactions chemical reactions and gravitational contraction nuclear fusion and gravitational contraction nuclear fusion and nuclear fission?

What is Nuclear fission is when a heavy nucleus split to release energy . it splits into two lesser nuclei.

Gravitational contraction:

is when there is collapse of an object in space due to the influence of its own gravity. This two phenomenon makes it possible for a satr to maintain its thermal (heat )pressure.

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An airplane has wings, each with area A, designed so that air flows over the top of the wing at 265 m/s and underneath the wing
exis [7]

Answer

given,

Pressure on the top wing = 265 m/s

speed of underneath wings = 234 m/s

mass of the airplane =  7.2 × 10³ kg

density of air =  1.29 kg/m³

using Bernoulli's equation

 P_1 + \dfrac{1}{2}\rho v_1^2 = P_2 + \dfrac{1}{2}\rho v_2^2

 \Delta P =\dfrac{1}{2}\rho (v_2^2-v_1^2)

 \Delta P =\dfrac{1}{2}\times 1.29\times (265^2-234^2)

 \Delta P =9977.5 Pa

Applying newtons second law

2 Δ P x A - mg = 0

A =\dfrac{mg}{2\Delta P}

A =\dfrac{7.2\times 10^3 \times 9.8}{2\times 9977.5}

    A = 3.53 m²

7 0
3 years ago
Why is tornadoes hitting the east coast of the USA?
OLga [1]

Answer:

The outbreak of tornadoes that tore across the Gulf and the East Coast Tuesday and Wednesday was unusual for two reasons. For one thing, the severe weather encompassed a significant swath of the country. For another, winter is the least likely time for tornadic thunderstorms.

Explanation:

The outbreak of tornadoes that tore across the Gulf and the East Coast Tuesday and Wednesday was unusual for two reasons. For one thing, the severe weather encompassed a significant swath of the country. For another, winter is the least likely time for tornadic thunderstorms.

And yet tornadoes are an expected part of life in the United States—especially in the multi-state area known as Tornado Alley. (Florida, too, sees a disproportionately high number of tornadoes, because of its frequent thunderstorms.) The United States gets more tornadoes, by far, than any other place on the planet. It averages about 1,250 twisters a year. Canada, which sees about 100 tornadoes per year, is a “distant second,” according to the National Centers for Environmental Information.

8 0
3 years ago
Skylar goes to a pumpkin patch and pick out a pumpkin that has a mass of 6000 grams how many kilograms is the pumpkin
Alex
1000g = 1kg
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6 0
3 years ago
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Milk in a hot cup can be cooled by pouring its back and fourth between the bigger cup.How does this action help to cool milk?
kotegsom [21]
Put it in the fridge
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A plant worker accidentally breathes some stored gaseous tritium, a beta emitter with maximum particle energy of 0.0186 MeV. The
andrey2020 [161]

Answer:

400 milli-rems

Solution:

As per the question;

Maximum energy of particle, E_{m} = 0.0186\ MeV

Weight, w = 1 kg

Energy absorbed, E = 4\times 10^{- 3}\ J

Now,

Equivalent dose is given by:

D_{eq} = \frac{E}{w}  =\frac{4\times 10^{- 3}}{1} = 4\times 10^{- 3}\ J/kg

1 Gy = 1 J/kg

Also,

1 Gy = 1\times 10^{5}\ milli-rems

Therefore,

Dose equivalent in milli-rems is given by:

D_{eq} = 4\times 10^{- 3}\times 1\times 10^{5} = 400\ milli-rems

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