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3 years ago

4^-2 * 7^-2 select the equivalent expression

Mathematics

1 answer:

Harrizon [31]3 years ago

8 0

Answer:

Step-by-step explanation:

You haven't provided the expressions to choose from.

4⁻² × 7⁻² = (4×7)⁻² = 28⁻² = 1/28²

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Help Picture attached

Leni [432]

what i did to get my answer was 13*6*6 because the whole circle is 12 and so i got 468.

6 0

3 years ago

A car valued at £18000 at the start of 2017, depreciated in value by 5% each year for 3 years. How much did it lose in value ove

Anna11 [10]

Answer:

The amount lost over the 3 years s 2567.25£

Explanation:

$\mathrm{F}=\mathrm{I} \times\left(1-\left(\frac{r}{100}\right)\right)^{\mathrm{n}}$

where F = final value after n years

I = initial value of the car in 2017 = £18000 (given)

Since the value is depreciated 5% every year for 3 years,

r = percentage rate of depreciation = 5% (given)

n = 3 years

Substituting these values in formula, we get

$\mathrm{F}=18000 \times\left(1-\frac{5}{100}\right)^{3}$

= $18000 \times\left(\frac{95}{100}\right)^{3}$

= 15432.75£ which is the value of the car after 3 years

Finally 18000-15432.75 = 2567.25£ is the amount lost over this period.

6 0

3 years ago

Answer 1,2 and 3 and challenge thank you

Nadusha1986 [10]

NUMBER 2 is 240 because 6 times 4 times 10 is equal to 240. I am still working on the others

7 0

3 years ago

Hamster111 yes please

Rufina [12.5K]

Answer:

Indeed

Step-by-step explanation:

3 0

2 years ago

There are three clubs at Redwood High School: Debate, Student council, and Key club. There are 1000 students in the school. And

hram777 [196]

Answer:

The number of students in the key club is 490

Step-by-step explanation:

The given parameters are;

The number of student in the school = 1000

The total number of student in the debate club = 310

The total number of student in the student council = 650

The total number of student who are in debate and student council = 170

The total number of student who are in both debate and the key club = 150

The total number of student who are in both student council and the key club = 180

The number of students who are in all three clubs = 50

Therefore, we have;

Let A represent the number of students in the debate club

Let B represent the number of students in the student council

Let C represent the number of students in the key club

We have;

n(A∪B∪C) = n(A) + n(B) + n(C) - n(A∩B) - n(B∩C) - n(C∩A) + n(A∩B∩C)

Where;

n(A∪B∪C) = 1000

n(A) = 310

n(B) = 650

n(A∩B) = 170

n(B∩C) = 180

n(C∩A) = 150

n(A∩B∩C) = 50

Therefore;

n(C) = n(A∪B∪C) - (n(A) + n(B) - n(A∩B) - n(B∩C) - n(C∩A) + n(A∩B∩C))

Substituting the values gives;

n(C) = 1000 - (310 + 650 - 170 - 180 - 150 + 50) = 490

The number of students in the key club, n(C) = 490.

5 0

3 years ago