<span>0.5p - 3.45 = -1.2 ⇒ p=4.5</span>
Answer:
1
Step-by-step explanation:
There are about 110,000 days in 300 years, so the expected number of failures is about 10/11 ≈ 1.
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This assumes the launch conditions are identical for each of the launches, or that whatever variation there might be has no effect on the probability. These are bad assumptions.
Answer:
Step-by-step explanation:
5x+2x+7=7x+7
X = 0, for starters. Also, X + Y = Y( true for any Y value when X = 0)
I think it is c>2 , sorry if incorrect :(
