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Ahat [919]
3 years ago
13

What is the length of BC Round to the nearest tenth

Mathematics
1 answer:
Elenna [48]3 years ago
7 0

Answer:

Step-by-step explanation :4.0148 rounded to the nearest thousand is 0, but if you meant rounded to the nearest thousandth, it would be 4.015 because the 8 in the ten thousandth column would cause the 4 in the thousandth column to round up to 5.

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Interpreting the inequality, it is found that the correct option is given by F.

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  • The first equation is of the line.
  • The equal sign is present in the inequality, which means that the line is not dashed, which removes option G.

In standard form, the equation of the line is:

x + 2y = 6

2y = 6 - x

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Thus it is a decreasing line, which removes options J.

  • We are interested in the region on the plane below the line, that is, less than the line, which removes option H.

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  • As for the second equation, the normalized equation is:

3x^2 + 3y^2 = 12

3(x^2 + y^2) = 12

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  • Thus, a circle centered at the origin and with radius 2.
  • Now, we have to check if the line x + 2y - 6 = 0, with coefficients a = 1, b = 2, c = -6, intersects the circle, of centre x = 0, y = 0
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d = \sqrt{\frac{|ax + by + c|}{a^2 + b^2}}

  • Considering the coefficients of the line and the center of the circle.

d = \sqrt{\frac{|1(0) + 2(0) - 6|}{1^2 + 2^2}} = \sqrt{\frac{6}{5}} = 1.1

  • This distance is less than the radius, thus, the line intersects the circle, which removes option K, and states that the correct option is given by F.

A similar problem is given at brainly.com/question/16505684

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