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swat32
3 years ago
8

!!Find the area of the shaded region!! (worth 20 points)

Mathematics
1 answer:
Leona [35]3 years ago
6 0

Answer:

shaded area = 8.7 ft²

Step-by-step explanation:

area of circle = πr² = (3.14)(4²) = 50.24 ft²

apothem of hexagon = (sin 60° x 4) = 3.464

area of hexagon = 1/2(3.464)(6)(4) = 41.56 ft²

50.24 - 41.56 = 8.68 ft²

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Pls help me find f(0)
KatRina [158]
F(x)=3x^2+2x+1. if f(0), we need to plug it in to see the overall equation, so, f(0)=3(0)^2+2(0)+1. f(0)=1.
4 0
3 years ago
A sweatshirt that was originally priced at $42.50 has been marked down to $34.00. What is the percent decrease?
vichka [17]

Answer:

The answer is 20%

I hope this helps :)


6 0
3 years ago
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The coordinates of the vertices of △RST are R(−3,1), S(−1,4), and T(3,1) .
Ghella [55]
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3 0
3 years ago
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What is the final amount if 2250 is decreased by 2% followed by a further 3% decrease?
Marrrta [24]

Answer:

2138.85

Step-by-step explanation:

2250 decreased by 2% is

2% of 2250 subtracted from 2250

That’s

2% /100% x 2250

0.02 x 2250

45

So, decrease = 2250 - 45

= 2205

Now 2205 decreased by 3%

3% of 2205

3% /100% x 2205

0.03 x 2205

66.15

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= 2138.85

3 0
3 years ago
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The probability a randomly selected household owns corporate stock is 0.54. The probability a randomly selected household has no
34kurt

Answer:

30% probability a randomly selected household has no Internet access given the household owns corporate stock

Step-by-step explanation:

I am going to say that we have two events.

Event A: Owning corporate stock. So P(A) = 0.54.

Event B: Having no internet access. So P(B) = 0.3.

Since they are independent events, we can apply the conditional probability formula, which is:

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probabilitty of event B happening given that A happened. We want to find this.

P(A \cap B) is the probability of both events happening.

Since they are independent

P(A \cap B) = P(A)P(B) = 0.54*0.3

So

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.54*0.3}{0.54} = 0.3

30% probability a randomly selected household has no Internet access given the household owns corporate stock

8 0
3 years ago
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