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pickupchik [31]
2 years ago
8

the hooded men rushed out of town at 100 miles per hour one hour later the masked men left town in pursuit at 125 mph how many h

ours did it take the masked men to catch up to the hooded men
Mathematics
2 answers:
n200080 [17]2 years ago
5 0

Question:

the hooded men rushed out of town at 100 miles per hour one hour later the masked men left town in pursuit at 125 mph how many hours did it take the masked men to catch up to the hooded men

Answer:

12.5

Step-by-step explanation:

This doesn't say it in the question but the hooded man drove 125 miles,
his speed was 100 mph.

The masked man drove also drove 125 miles but he drove at 125 mph.

Ok sorry lets make this simpler.

divide 1250 by 100 and your answer is:

12.5

So, it took the masked man 12.5 hours to catch up with the hooded man.

nlexa [21]2 years ago
3 0

Answer:

It took 12.5 hours to catch up with the men

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The area of a rectangle is 144cm squared. The length of the rectangle is 8 cm. What is the measure of the width of the rectangle
Gelneren [198K]
<h2>Greetings!</h2>

Answer:

The width is 18cm

Step-by-step explanation:

If the equation of the area of a rectangle is:

Area = length * width

Then you substitute in the values you know:

144 = 8 * width

To find the width you need to rearrange the formula to make the width the subject. Do this by dividing the area by the length:

Width = 144 / 8

Width = 18

So the width is 18cm


<h2>Hope this helps!</h2>
3 0
3 years ago
The radioactive element americium-241 has a half-life of 432 years. How many years will it take a 10 gram mass of americium-241
geniusboy [140]
<h2>Answer: 816 years</h2>

This problem can be solved using the <u>Radioactive Half Life Formula: </u>

<u />

A=A_{o}.2^{\frac{-t}{h}}   (1)

Where:

A=2.7g is the final amount of the material

A_{o}=10g is the initial amount of the material

t is the time elapsed  (the quantity we are asked to find)

h=432y is the half life of americium-241

Knowing this, let's find t from (1):

2.7g=(10g).2^{\frac{-t}{432y}}  

\frac{2.7g}{10g}=2^{\frac{-t}{432y}}  

0.27g=2^{\frac{-t}{432y}}  

Applying natural logarithm in both sides:

ln(0.27g)=ln(2^{\frac{-t}{432y}})  

-1.309=-\frac{t}{432y}ln(2)  

-t=\frac{(-1.309)(432y)}{0.693}  

<u></u>

<u>Finally:</u>

t=816y

3 0
3 years ago
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For this case, we must find the quotient of

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Answer:

Option B


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Which ordered pair is a solution of the equations y=-5/4x-2
sashaice [31]
The answer is C. That would be ur answer
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