Question

Find the surface area of the right square pyramid. Round your answer to the nearest hundredth.

Answer 1

ANSWER

C. 145.75 yd²

EXPLANATION

First we need to calculate the area of the four triangular faces.

The lateral surface area

$= 4 \times \frac{1}{2} \times 5.3 \times 11.1$

$= 117.66 {yd}^{2}$

The area of the base is

$= 5.3 \times 5.3$

$= 28.09$

To find the total surface area, we add the area of the square base to the area of the 4 triangular faces.

Therefore the total surface area is

$= 117.66 + 8.09 = 145.75 {yd}^{2}$

Answer 2

Answer: Option C.

Step-by-step explanation:

To calculate the surface area of the right square pyramid, you need to use the following formula:

$SA=\frac{1}{2}(4s)(l)+(s^2)$

Where  "s" is the length of any side of the base and "l" is the slant height.

You can identify in the figure that:

$s=5.3yd\\l=11.1yd$

Therefore, substituting these values into the formula, you get this result:

$SA=\frac{1}{2}(4(5.3yd))(11.1yd)+((5.3yd)^2)\\\\SA=145.75yd^2$