Solve 2 2 2 + + (22 − 2) = 0, ≠ 0, ≥ 0

Chevy has some yarn that he wants to use to make hats and scarves. Each hat uses 0.20.20, point, 2 kilograms of yarn and each sc

Rashid [163]

Answer:

The system of equation that represent this situations are;

$\left \{ {{h+s=15} \atop {0.2h+0.1s=2}} \right.$

Also 5 hats and 10 scarves can be prepared from 2 kg of yarn.

Step-by-step explanation:

Let number of hat Chevy makes be h.

Also Let number of scarves Chevy makes be s.

Given:

Total Amount of yarns = 2 kg

Total number of items = 15

Since Items need to make are hat and scarves.

Hence the equation can be represented as;

$h+s=15 \ \ \ \ equation \ 1$

Again Given:

Each hat uses 0.2 kilograms of yarn.

each scarf uses 0.1 kilograms of yarn.

Hence the equation can be represented as;

$0.2h+0.1s=2 \ \ \ \ \ equation \ 2$

Hence the system of equation that represent this situations are;

$\left \{ {{h+s=15} \atop {0.2h+0.1s=2}} \right.$

Now Solving these to find number of hats and number of scarves.

Multiplying equation 2 with 10 we get;

$10(0.2h+0.1s)=2\times 10\\10\times0.2h+10\times0.1s=20\\2h+s =20 \ \ \ \ \ equation \ 3$

Now Subtracting equation 1 from equation 3 we get;

$(2h+s)- (h+s) =20-15\\2h+s-h-s=5\\h= 5$

Now Substituting the value of h in equation 1 we get;

$h+s= 15\\5+s =15\\s=15-5\\s=10$

Hence 5 hats and 10 scarves can be prepared from 2 kg of yarn.

5 0

3 years ago

What the property says that 5+13=13+5

Pavlova-9 [17]

Answer: its true

Step-by-step explanation:

i got it right

4 0

2 years ago

Read 2 more answers

How do you fine out if y is a linear function of x on a graph

mote1985 [20]

Answer: If a vertical line can be drawn to touch the graph of a function in more than one place, then is NOT a function of . If it is not possible to draw a vertical line to touch the graph of a function in more than one place, then y is a function of x.

6 0

2 years ago

(Segment Proofs)

Anni [7]

Answer:

It's proved below

Step-by-step explanation:

We are given;

- K is the midpoint of JL

- M is the midpoint of LN

By definition of mid points, we can say that;

JK = KL and LM = MN

Now, we are given that JK = MN.

Thus, by substitution, we can deduce that; KL = LM

Thus is because JK can be replaced with KL and MN can be replaced with LM.

Thus, it is proved that KL = LM

4 0

2 years ago

Find the absolute maximum and absolute minimum values of f on the given interval. (If an answer does not exist, enter DNE.)

vodka [1.7K]

Answer:

absolute max is 120 and absolute min is -8

Step-by-step explanation:

Find critical numbers

f'(x) = 3x^2 - 12x + 9 = 0

= 3(x^2 - 4x + 3) = 0

3(x-3)(x-1) = 0

(x-3) = 0 or (x-1)=0

x = 1,3

Test them!

x<1 Sign of f' on this interval is positive

1<x<3 Sign of f' on this interval is negative

x>3 Sign of f' on this interval is positive

f(x) changes from positive to negative at x = 1 which means there is a relative maximum here.

f(x) changes from negative to positive at x = 3 which means there is a relative minimum here.

Test the endpoints to find the absolute max and min.

f(-1) = -8

f(1) = 12

f(3) = 8

f(7) = 120

The absolute maximum value of f is 120 and the absolute minimum value of f is -8.

7 0

3 years ago