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stiv31 [10]
3 years ago
12

Calculate how many grams of sodium chloride we would need to make a solution with the same molarity of seawater, which is about

0.598 M.
Chemistry
1 answer:
aliya0001 [1]3 years ago
7 0

Answer:

34.92 grams NaCl (in 1 L of solution)

Explanation:

The chemical formula of sodium chloride is NaCl. From the formula, we can calculate the molar mass of NaCl:

MM(NaCl)= MM(Na) + MM(Cl) = 23 g/mol + 35.4 g/mol = 58.4 g/mol

A solution of NaCl with a molarity of 0.598 M has 0.598 moles of NaCl per liter of solution. So, we multiply the moles by the molar mass of NaCl to calculate the mass we need:

mass of NaCl = 0.598 mol x 58.4 g/mol = 34.92 g NaCl

Therefore, we need 34.92 grams of NaCl to prepare 1 liter of a solution with a molarity of 0.598 M.

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Answer:

The new pressure is 44.4 kPa.

Explanation:

We have,

Initial volume, V_1=22\ ml

Initial pressure, P_1= 101.0\ kPa

It is required to find the new pressure when the volume is increased to 50 ml. The relationship between pressure and volume is known as Boyle's law.

PV=k\\\\P_1V_1=P_2V_2

P_2 is final pressure

P_2=\dfrac{P_1V_1}{V_2}\\\\P_2=\dfrac{22\times 101\times 10^3}{50}\\\\P_2=44440\ Pa\\\\P_2=44.4\ kPa

So, new pressure is 44.4 kPa.

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