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4 years ago

14

element that is neither a non-metal nor a metalloid, and is characterized by thin, dark grey filaments exhibiting magnetic prope

rties

1 answer:

Digiron [165]4 years ago

6 0

Yes would you explain better

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0.446 g of hydrogen gas fills a 5.0 L bag determine the density of hydrogen

Oduvanchick [21]

The density of hydrogen : ρ = 0.0892 g/L

<h3>Further explanation</h3>

Given

mass of Hydrogen : 0.446 g

Volume = 5 L

Required

The density

Solution

Density is a quantity derived from the mass and volume

Density is the ratio of mass per unit volume

The unit of density can be expressed in g/cm³, kg/m³, or g/L

Density formula:

$\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}$

Input the value :

ρ = m : V

ρ = 0.446 g : 5 L

ρ = 0.0892 g/L

5 0

3 years ago

How much potassium chloride is needed to make 0.500 m solution with 1.50 L of water?

Andrew [12]

Answer:

55.9 g KCl.

Explanation:

Hello there!

In this case, according to the definition of molality for the 0.500-molar solution, we need to divide the moles of solute (potassium chloride) over the kilograms of solvent as shown below:

$m=\frac{mol}{kilograms}$

Thus, solving for the moles of solute, we obtain:

$mol=m*kilograms$

Since the density of water is 1 kg/L, we obtain the following moles:

$mol=0.500mol/kg*1.50kg\\\\mol=0.75mol$

Next, since the molar mass of KCl is 74.5513 g/mol, the mass would be:

$0.75mol*\frac{74.5513g}{1mol}\\\\55.9g \ KCl$

Regards!

4 0

3 years ago

What are 2 ways to give an object potential energy?

natita [175]

There are several ways to give an object potential energy. One can move the object against the force of gravity to increase. One can also stretch an object out or put pressure on it.

7 0

4 years ago

Fill in the gaps. Will give BRAINLIEST and 5 starss!!!

Stells [14]

First gap is BY USING MAGNETS
2nd is ELECTROLYSIS
3rd is EVAPORATION

7 0

3 years ago

The thermite reaction reacts iron (III) oxide, Fe2O3, with aluminium powder,Al, the form aluminium oxide, Al2O3 and iron, Fe.

lara [203]

Answer:

<u><em>This answer assumes that the strated "16.0g of iron" was meant to be 16.0 grams of iron(III) oxide.</em></u>

Explanation:

To start, the thermite equation must be balanced.

I find:

1Fe2O3 + 2Al = 1Al2O3 + 2Fe

This tells us we need 2 moles of Al for every 1 mole of Fe2O3.

Now calculate the moles of each reactant:

Moles Fe2O3: 16.0 g/159.7 g/mole = <u>0.100 moles Fe2O3</u>

Moles Al: 8.1 /26.98 g/mole = <u>0.300 moles Al</u>

The balanced equation says that in order to react all of the Fe2O3 we'd need twice that amount (in moles) of the Al. (0.100 moles Fe2O3)*(2) = 0.200 moles Al.

<u>Which of the two reactants is the limiting reagent?</u>

We have more than enough moles of Al to react with 0.10 moles of Fe2O3. (We have 0.300 moles Al and all we need is 0.200 moles to react with the 0.10 moles of Fe2O3. <em>Fe2O3 is the limiting reagent.</em>

<u><em>Calculate the maximum mass of iron of iron that could be formed using these quantities of reactants.</em></u>

The balanced equation tells us that we will obtain 2 moles of Fe for every 1 mole of Fe2O3 consumed. Since Fe2O3 is the limiting reagent, we will assume that it completely reacts. That means 0.1 moles of Fe2O3 is reacted. Since we expect twice that many moles of Fe, we should obtain 0.200 moles of Fe. At 55.85 g/mole, we should obtain:

(0.200 moles Fe)*(55.85 g Fe/mole Fe) = 11.2 grams Fe

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5 0

2 years ago