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USPshnik [31]
2 years ago
10

What is the enthalpy of the overall chemical equation

Chemistry
2 answers:
Dimas [21]2 years ago
5 0

Recall that standard enthalpies of formation can be either positive or negative. The enthalpy of formation of carbon dioxide at 298.15K is ΔH f = -393.5 kJ/mol CO 2(g). Write the chemical equation for the formation of CO2

12345 [234]2 years ago
3 0

Answer:

The enthalpy of the overall chemical equation is -304.1 kJ

Explanation:

Enthalpy is an additive property. The overall chemical equation can be obtained by summing up all three elementary steps. So enthalpy of overall reaction is summation of enthalpy changes in each steps.

                    NO(g)+O_{3}(g)\rightarrow NO_{2}(g)+O_{2}(g)

                    \frac{3}{2}O_{2}(g)\rightarrow O_{3}(g)

                    O(g)\rightarrow \frac{1}{2}O_{2}(g)

                 ----------------------------------------------------------------------------------------

                     NO(g)+O(g)\rightarrow NO_{2}(g)

Enthalpy of overall reaction = \Delta H_{1}+\Delta H_{2}+\Delta H_{3}

                                               = (-198.9+142.3-247.5) kJ

                                                = -304.1 kJ

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How many grams of HNO3 are produced when 59.0 g of NO2 completely reacts?
Anettt [7]

Answer:

53.7 grams of HNO3 will be produced

Explanation:

Step 1: Data given

Mass of NO2 = 59.0 grams

Molar mass NO2 = 46.0 g/mol

Step 2: The balanced equation

3NO2 + H2O→ 2HNO3 + NO

Step 3: Calculate moles NO2

Moles NO2 = 59.0 grams / 46.0 g/mol

Moles NO2 = 1.28 moles

Step 4: Calculate moles HNO3

For 3 moles NO2 we need 1 mol H2O to produce 2 moles HNO3 and 1 mol NO

For 1.28 moles NO2 we'll have 2/3 * 1.28 =0.853 moles HNO3

Step 7: Calculate mass HNO3

Mass HNO3 = 0.853 moles * 63.01 g/mol

Mass HNO3 = 53.7 grams

53.7 grams of HNO3 will be produced

3 0
3 years ago
What is the concentration of 10.00 mL of HBr if it takes 16.73 mL of a 0.253 M LiOH solution to neutralize it?
Leni [432]
First. let's write the reaction formula: HBr +LiOH ----> LiBr + H₂O

let's get the moles of LiOH first

moles= Molarity x Liters

moles= 0.253 M x 0.01673 Liter= 0.00423 moles LiOH

using the balanced equation, you can see that 1 mol LiOH is equal to 1 mol HBr. so:

0.00423 mol LiOH = 0.00423 mol HBr

now let's find the concentration

molarity= mol/ Liters

0.00423 mol/ 0.01000 Liters= 0.423 M
3 0
3 years ago
An analytical chemist weighs out 0.188 g of an unknown triprotic acid into a 250 mL volumetric flask and dilutes to the mark wit
Anon25 [30]

<u>Answer:</u> The molar mass of unknown triprotic acid is 97.66 g/mol

<u>Explanation:</u>

To calculate the molarity of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of triprotic acid

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=3\\M_1=?M\\V_1=250mL\\n_2=1\\M_2=0.0600M\\V_2=95.9mL

Putting values in above equation, we get:

3\times M_1\times 250=1\times 0.0600\times 95.9\\\\M_1=0.0077M

To calculate the molecular mass of solute, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Molarity of solution = 0.0077 M

Given mass of triprotic acid = 0.188 g

Volume of solution = 250 mL

Putting values in above equation, we get:

0.0077M=\frac{0.188\times 1000}{\text{Molar mass of triprotic acid}\times 250}\\\\\text{Molar mass of triprotic acid}=97.66g/mol

Hence, the molar mass of unknown triprotic acid is 97.66 g/mol

7 0
2 years ago
Can someone explain to me step by step with the equation on how to do it thx
Tasya [4]

Answer:

h=1

c=12

there 8 h

then there are 5 c

Explanation:

6 0
3 years ago
The diagram shows different forms of thermal energy transfer.
omeli [17]
A. conduction
that is the correct answer
6 0
2 years ago
Read 2 more answers
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