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USPshnik [31]
2 years ago
10

What is the enthalpy of the overall chemical equation

Chemistry
2 answers:
Dimas [21]2 years ago
5 0

Recall that standard enthalpies of formation can be either positive or negative. The enthalpy of formation of carbon dioxide at 298.15K is ΔH f = -393.5 kJ/mol CO 2(g). Write the chemical equation for the formation of CO2

12345 [234]2 years ago
3 0

Answer:

The enthalpy of the overall chemical equation is -304.1 kJ

Explanation:

Enthalpy is an additive property. The overall chemical equation can be obtained by summing up all three elementary steps. So enthalpy of overall reaction is summation of enthalpy changes in each steps.

                    NO(g)+O_{3}(g)\rightarrow NO_{2}(g)+O_{2}(g)

                    \frac{3}{2}O_{2}(g)\rightarrow O_{3}(g)

                    O(g)\rightarrow \frac{1}{2}O_{2}(g)

                 ----------------------------------------------------------------------------------------

                     NO(g)+O(g)\rightarrow NO_{2}(g)

Enthalpy of overall reaction = \Delta H_{1}+\Delta H_{2}+\Delta H_{3}

                                               = (-198.9+142.3-247.5) kJ

                                                = -304.1 kJ

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The earths crust and the skin of rock on the outer layer of earth.
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Determine the empirical formula for C6H3Br3.
Mazyrski [523]

Answer:

C2HBr

Explanation:

The empirical formula is like the simpliest form so divide all by 3 and get the above formula.

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2 years ago
A 3.0 L solution contains 73.5 g of H2SO4. Calculate the molar concentration of the solution.
kozerog [31]
C_{m}=\frac{m}{MV}=\frac{73,5g}{98\frac{g}{mol}*3L}=0,25M\\\\
C_{1}V_{1}=C_{2}V_{2}\\\\
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6 0
3 years ago
675 g of carbon tetrabromide is equivalent to how many
VARVARA [1.3K]
<h3>Answer:</h3>

2.04 mol CBr₄

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Organic</u>

  • Writing Organic Compounds
  • Writing Covalent Compounds
  • Organic Prefixes

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

675 g CBr₄

<u>Step 2: Identify Conversions</u>

Molar Mass of C - 12.01 g/mol

Molar Mass of Br - 79.90 g/mol

Molar Mass of CBr₄ - 12.01 + 4(79.90) = 331.61 g/mol

<u>Step 3: Convert</u>

<u />\displaystyle 675 \ g \ CBr_4(\frac{1 \ mol \ CBr_4}{331.61 \ g \ CBr_4}) = 2.03552 \ mol \ CBr_4<u />

<u />

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

2.03552 mol CBr₄ ≈ 2.04 mol CBr₄

7 0
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8 0
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