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nydimaria [60]
4 years ago
5

Help me please thx so much have a good one

Mathematics
1 answer:
stira [4]4 years ago
6 0
Downloaded Photomath, it’s going to help you a lot, also it’s free.
You might be interested in
What three numbers equal 918
Anna35 [415]
330+305+283=918

hope this helps
3 0
3 years ago
The graph of an equation with a negative discriminant always has which characteristic? ​
Vanyuwa [196]

Answer:

answer below

Step-by-step explanation:

equation with a negative discriminant: negative number under the square root

1. will produce imaginary number "i"

2. the function will get two complex solutions

6 0
3 years ago
3. A man of mass 80 kg standing at the top of a tall
Alex

Step-by-step explanation:

Gravitational potential energy is:

PE = mgh

Given PE = 96000 J and m = 80 kg:

96000 J = (80 kg) (9.8 m/s²) h

h ≈ 122 m

Round as needed.

3 0
3 years ago
When x is decreased by 129 and then that number is multiplied by 129, the result is 129. What is the value of x?
myrzilka [38]

Answer:

Step-by-step explanation:

twice the difference of a number and 3 is added to 4

4 0
3 years ago
A pharmacist receives a shipment of 21 bottles of a drug and has three of the bottles tested. If five of the 21 bottles are cont
blagie [28]

Answer:

The probability is 0.8722

Step-by-step explanation:

There are 21 bottles

5 of them are contaminated.

there are 21 - 5 = 16 non-contaminated bottles.

So, if we grab a bottle at random, the probability that this bottle is contaminated will be equal to the quotient between the number of contaminated bottles and the total number of bottles, this is:

p = 5/21

Now we want to find the probability that, for 3 tested bottles, that less than two (0 or 1 ) are contaminated.

Let's see each case on its own.

0 bottles:

The probability of getting a non-contaminated bottle in the first try is equal to the quotient between the number of non-contaminated bottles and the total number of bottles, this is:

p₁ = 16/21

For the second bottle is the same, but because one non-contaminated bottle was drawn before, now there are 15 non-contaminated bottles and 20 bottles in total, so now the probability is:

p₂ = 15/20

and similarly, for the third bottle the probability is:

p₃ = 14/19

The joint probability is the product of the individual probabilities, we get:

P = p₁*p₂*p₃ = (16/21)*(15/20)*(14/19) = 0.4211

Now the case that one bottle is contaminated.

Let's assume that the first one is contaminated.

The probability of getting a contaminated bottle in the first draw is equal to the quotient between the number of contaminated bottles and the total number of bottles, so:

p₁ = 5/21

For the second bottle, we want a non-contaminated one, there are 16 non-contaminated bottles and 20 bottles left, so here the probability is:

p₂ = 16/20

and for the third bottle we have the probability:

p₃ = 15/19

The joint probability is:

p = p₁*p₂*p₃ = (5/21)*(16/20)*(15/19)

Also notice that we only looked at the case where the first bottle is contaminated, we also have the case where the second one is contaminated and the case where the third one is  contaminated, so there are 3 permutations, then the probability of having one contaminated bottle is:

Q = 3*p = 3*(5/21)*(16/20)*(15/19) = 0.4511

Then the probability of having less than two contaminated bottles is:

probability = P + Q = 0.4211 + 0.4511 = 0.8722

8 0
3 years ago
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