B. the inner core has a higher temp than the outer core and the pressure is greater for the inner core witch makes it a solid. I'm not the smartest bean out there but I hoped this helped
Explanation:
1.Belonging to a(n)
is important to
most adolescents and serves several functions. G. clique
2. A person's physical and biological makeup is his or her. C gender identity
3. According to Erik Erikson, adolescents go
through a(n)
a time of inner con-
flict in which they worry about their identities. E identity crisis
4.is an eating disorder in which an
individual refuses to eat and loses weight. J.anorexia nervosa
5.5. The biological event that marks the end of
childhood is A puberty
6.Albert Bandura's belief that individuals develop
by interacting with others is referred to as the
of development. F social learning theory
7. Feet that are too large for the body is an exam-
or the condition of uneven
growth or maturation of bodily parts. b. asynchrony
8.A person's
is the standard of how a
person with a given gender identity is supposed
to behave. D gender role
9.Oversimplified or prejudiced opinions and atti-
tudes concerning the way men or women
should behave are called. I.gender stereotypes
10.An adolescent's fear of being set apart from oth-
ers leads to
among peer group
members.
ple of . H conformity
Most adult stem cells come from the bone marrow.
Answer:
Uno de los progenitores es heterocigoto para color naranja (Nn) y el otro parental es homocigoto recesivo para gris (nn). Al haber una cruza entre un homocigoto recesivo y un heterocigoto, la 50% de la progenie expresa color naranja (Nn), mientras que el otro 50% expresa color gris (nn).
Explanation:
<u>Datos disponibles:</u>
- Cruce entre peces naranjas y peces grises
- 50% de la F1 son peces grises
- Naranja dominante sobre gris
Podemos nombrar el alelo dominante para color naranja <em>N</em>, y al alelo recesivo para color gris <em>n</em>.
Para que en un cruce entre dos fenotipos distintos, el 50% de la primer camada exprese uno de estos fenotipos, entonces uno de los parentales debe ser heterocigoto, mientras que el otro parental debe ser homocigoto recesivo. De esta forma 50% de la primera generación expresara uno de los fenotipos, mientras que el otro 50% expresará el otro fenotipo.
Supongamos que uno de los parentales lleva el genotipo <em>Nn</em>, y el otro parental es <em>nn</em>.
Cruce:
Parental) Nn x nn
Gametas) N n n n
Fenotipos) Naranja Gris
Cuadro de Punnett) N n
n Nn nn
n Nn nn
F1) 2/4 = 1/2 = 50% de la progenie tendrá genotipo heterocigoto, Nn
2/4 = 1/2 = 50% de la progenie tendrá genotipo homocigota recesivo,
nn
50% de la progenie será color naranja (Nn)
50% de la progenie será color gris (nn)
