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3 years ago

Use the long division method to find the result when 6x^3+17x^2+19x+28 is divided by 3x+7.

Mathematics

2 answers:

kari74 [83]3 years ago

4 0

Answer:

2x^2 + x + 4

Step-by-step explanation:

Use Polynomial division.

joja [24]3 years ago

4 0

Answer:

2x2 + x + 4

Step-by-step explanation:

Theres your answer good luck

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Use the rule for y= -6x +8 to find the output if the input is x=20

lisov135 [29]

Answer:

The output of the function y = -6x + 8 when the input is x = 20 is -112.

Step-by-step explanation:

y = -6x + 8

Input the value x = 20.

y = -6(20) + 8

Multiply -6 and 20.

y = -120 + 8

Add -120 and 8.

y = -112.

8 0

3 years ago

Read the numbers and decide what the next number should be. 256 196 144 100 64 36 16

Tatiana [17]

340? TBD add the two numbers.

4 0

4 years ago

Read 2 more answers

It takes Sarah 50 minutes to walk to her friend's house 1 3/4 miles away. What is her walking pace in miles per hour?

tankabanditka [31]

Divide 50 by 1 3/4 to get your answer for miles per minute then multiply that by sixty to get hours. then write it as _mph

8 0

3 years ago

Y=1/3x-3<br> Y=-x+5 <br> How do I solve

ehidna [41]

Since both equations are equal to y, we can just combine them like this:

1/3x-3=-x+5

1/3x=-x+8

4/3x=8 (since x is 1x which is 3/3x)

x=6

Plug x back in:

y=-6+5

y=-1

So x=6 and y=-1

Hope this helped!

4 0

4 years ago

A cellular phone company monitors monthly phone usage. The following data represent the monthly phone use of one particular cust

Fiesta28 [93]

SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Write the given set of values

$321,397,559,454,475,324,482,558,369,513,385,360,459,403,498,477,361,366,372,320$

STEP 2: Write the formula for calculating the Standard deviation of a set of numbers

$\begin{gathered} S\tan dard\text{ deviation=}\sqrt[]{\frac{\sum^{}_{}(x_i-\bar{x})^2}{n-1}} \\ where\text{ }x_i\text{ are data points,} \\ \bar{x}\text{ is the mean} \\ \text{n is the number of values in the data set} \end{gathered}$

STEP 3: Calculate the mean

$\begin{gathered} \bar{x}=\frac{\sum ^{}_{}x_i}{n} \\ \bar{x}=\frac{\sum ^{}_{}(321,397,559,454,475,324,482,558,369,513,385,360,459,403,498,477,361,366,372,320)}{20} \\ \bar{x}=\frac{8453}{20}=422.65 \end{gathered}$

STEP 4: Calculate the Standard deviation

$\begin{gathered} S\tan dard\text{ deviation=}\sqrt[]{\frac{\sum^{}_{}(x_i-\bar{x})^2}{n-1}} \\ \sum ^{}_{}(x_i-\bar{x})^2\Rightarrow\text{Sum of squares of differences} \\ \Rightarrow10332.7225+657.9225+18591.3225+982.8225+2740.52251+9731.8225+3522.4225+18319.6225+2878.3225 \\ +8163.1225+1417.5225+3925.0225+1321.3225+386.1225+5677.6225+2953.9225+3800.7225 \\ +3209.2225+2565.4225+10537.0225 \\ \text{Sum}\Rightarrow108974.0275 \\ \\ S\tan dard\text{ deviation}=\sqrt[]{\frac{111714.55}{20-1}}=\sqrt[]{\frac{111714.55}{19}} \\ \Rightarrow\sqrt[]{5879.713158}=76.67928767 \\ \\ S\tan dard\text{ deviation}\approx76.68 \end{gathered}$

Hence, the standard deviation of the given set of numbers is approximately 76.68 to 2 decimal places.

STEP 5: Calculate the First and third quartile

$\begin{gathered} \text{IQR}=Q_3-Q_1 \\ \\ To\text{ get }Q_1 \\ We\text{ first arrange the data in ascending order} \\ \mathrm{Arrange\: the\: terms\: in\: ascending\: order} \\ 320,\: 321,\: 324,\: 360,\: 361,\: 366,\: 369,\: 372,\: 385,\: 397,\: 403,\: 454,\: 459,\: 475,\: 477,\: 482,\: 498,\: 513,\: 558,\: 559 \\ Q_1=(\frac{n+1}{4})th \\ Q_1=(\frac{20+1}{4})th=\frac{21}{4}th=5.25th\Rightarrow\frac{361+366}{2}=\frac{727}{2}=363.5 \\ \\ To\text{ get }Q_3 \\ Q_3=(\frac{3(n+1)}{4})th=\frac{3\times21}{4}=\frac{63}{4}=15.75th\Rightarrow\frac{477+482}{2}=\frac{959}{2}=479.5 \end{gathered}$

STEP 6: Find the Interquartile Range

$\begin{gathered} IQR=Q_3-Q_1 \\ \text{IQR}=479.5-363.5 \\ \text{IQR}=116 \end{gathered}$

Hence, the interquartile range of the data is 116

3 0

1 year ago