Answer:
For any normal distribution, the mean and the median will have the same value. For any normal distribution, the proportion corresponding to scores greater than z = +1.00 is exactly equal to the proportion corresponding to scores less than z = -1.00.
Step-by-step explanation:
Answer:
Each answer correct is 5 points so Doug got 40 points.
Step-by-step explanation:
Average rate of change = [H(100) - H(80)] / (100 - 80)
H(100) = 0.003(100)^2 + 0.07(100) - 0.027 = 0.003(10000) + 0.07(100) - 0.027 = 30 + 7 - 0.027 = 36.973
H(80) = 0.003(80)^2 + 0.07(80) - 0.027 = 0.003(6400) + 0.07(80) - 0.027 = 19.2 + 5.6 - 0.027 = 24.773
Average rate of change = (36.973 - 24.773)/(100 - 80) = 12.2/20 = 0.61
Answer: B
No its not possible I cant explain right now because I'm in class but I will later
The answer is C i believe
