Answer:
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Step-by-step explanation:
zjjxjxbz1+1+1++1+1++1
Thing I no this one I just forgot
Given :
- Area of the trapezium is 140 cm².
- Its height is 10 cm.
- One of the parallel side is 16 cm.
To Find :
Solution :
- Let the other parallel side be x
We know that,

Now, Substituting the given values in the formula :







Therefore,
- The other parallel side of the trapezium is 12 cm.