How do u draw a concave pentagon with exactly one pair of perpendicular sides
2 answers:
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Let us examine the given statements:
1. Over the interval [-2.5, 0.5], the local maximum is 2.
TRUE
2. As the x-values go to positive infinity, the function's values go to
negative infinity.
The opposite happens.
FALSE
3. The function is decreasing over the interval (-1, 0.75).
The function decreases in (-1, 0), but it increases in (0, 0.75).
FALSE
4. The function is negative for the interval [-2, 0].
The function is positive in [-2, -1). It is negative only in (-1, 0].
FALSE
1. Over the interval [-2.5, 0.5], the local maximum is 2.
TRUE
2. As the x-values go to positive infinity, the function's values go to
negative infinity.
The opposite happens.
FALSE
3. The function is decreasing over the interval (-1, 0.75).
The function decreases in (-1, 0), but it increases in (0, 0.75).
FALSE
4. The function is negative for the interval [-2, 0].
The function is positive in [-2, -1). It is negative only in (-1, 0].
FALSE
Answer:
x = 1.5 , y = 3 + 2at.
Step-by-step explanation:
For the parabola = 4aX ,
General form will be
(X = a , Y = 2at) ,
Thus , for the parabola = 6(x +8)
Here , a = 1.5 and Y from the above equation should be substituted by y - 3 and X must be substituted by x + 8. After substitution of the same we can use the general equation formula for this parabola also.
Thus , general equation comes out to be :-
x + 8 = 1.5 , y - 3 = 2at
x = 1.5 , y = 3 + 2at.