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skelet666 [1.2K]
3 years ago
8

How do u draw a concave pentagon with exactly one pair of perpendicular sides

Mathematics
2 answers:
Nutka1998 [239]3 years ago
6 0
Brain dump.... 
have you ever heard the expression cave in ?  when u see something (cave in) it looks like crater right? 
so just like that you know to draw to crater like objects perpendicular from each other 
perpendicular means <span>at an angle of 90° to a given line, plane, or surface.</span>
Elena L [17]3 years ago
6 0
Refer to the rough drawing I have attached.
Sides 1 and 2 are perpendicular.
Sides 4 and 5 create a concave angle.

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The figure is made up of a hemisphere and a cone. What is the exact volume of the figure. ___ in3 I need help
Akimi4 [234]
The answer would be 768<span>π</span>
4 0
4 years ago
Read 2 more answers
A lay came to the market to sell eggs . We first customer bought 1/2 of all her eggs and 1/2 of an egg. Her second customer boug
Bezzdna [24]

Given:

First customer bought 1/2 of all eggs of lady seller and 1/2 of an egg.

Her second customer bought 1/2 of all the remaining eggs and 1/2 of an egg.

At this point she had sold all her eggs.

To find:

The number of egg the lady have when she came to the market.

Solution:

Let x be the number of egg that the lady have when she came to the market.

First customer bought 1/2 of all eggs of lady seller and 1/2 of an egg. So, the number of remaining eggs after first customer is

x-\dfrac{1}{2}x-\dfrac{1}{2}=\dfrac{x}{2}-\dfrac{1}{2}

Her second customer bought 1/2 of all the remaining eggs and 1/2 of an egg.  So, the number of remining egg after second customer is

\text{Remaining eggs}=\dfrac{x}{2}-\dfrac{1}{2}-(\dfrac{x}{2}-\dfrac{1}{2})\times \dfrac{1}{2}-\dfrac{1}{2}

=\dfrac{x}{2}-\dfrac{1}{2}-\dfrac{x}{4}+\dfrac{1}{4}-\dfrac{1}{2}

=(\dfrac{x}{2}-\dfrac{x}{4})+(-\dfrac{1}{2}+\dfrac{1}{4}-\dfrac{1}{2})

=(\dfrac{2x-x}{4})+(\dfrac{-2+1-2}{4})

=\dfrac{x}{4}-\dfrac{3}{4}

At this point she had sold all her eggs. It means the remining eggs is 0.

\dfrac{x}{4}-\dfrac{3}{4}=0

\dfrac{x}{4}=\dfrac{3}{4}

Multiply both sides by 4.

x=3

Therefore, the lady came to the market is with 3 eggs.

8 0
3 years ago
How do I do this problem?
lions [1.4K]

Answer:

hey you can use scan and search

5 0
3 years ago
Read 2 more answers
I NEED HELP ASAP
Maru [420]

Answer:

1x + 4y = 4 ⇒ 6x + 24y = 24

6x -  8y = 0 ⇒ 6x -   8y = 0  

                              32y = 24

                               32     32

                                  y = 3/4

                    x + 4(3/4) = 4

                           x + 3 = 4

                               -3   -3

                                x = 1

                           (x, y) = (1, 3/4)

Step-by-step explanation:

up there :D

4 0
2 years ago
If a polynomial function f(x) has roots -8, 1, and 6i, what must also be a root of f(x)?
Naddik [55]

Answer:

it must also have the root : - 6i

Step-by-step explanation:

If a polynomial is expressed with real coefficients (which must be the case if it is a function f(x) in the Real coordinate system), then if it has a complex root "a+bi", it must also have for root the conjugate of that complex root.

This is because in order to render a polynomial with Real coefficients, the binomial factor  (x - (a+bi)) originated using the complex root would be able to eliminate the imaginary unit, only when multiplied by the binomial factor generated by its conjugate: (x - (a-bi)). This is shown below:

(x-(a+bi))*(x-(a-bi))=\\(x-a-bi)*(x-a+bi)=\\([x-a]-bi)*([x-a]+bi)=\\(x-a)^2-(bi)^2=\\(x-a)^2-b^2(-1)=\\(x-a)^2+b^2

where the imaginary unit has disappeared, making the expression real.

So in our case, a+bi is -6i (real part a=0, and imaginary part b=-6)

Then, the conjugate of this root would be: +6i, giving us the other complex root that also may be present in the real polynomial we are dealing with.

5 0
3 years ago
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