3) x² - 121 = 0
x² = 121
x' = +√121
x' = 11
_______________
x'' = - √121
x'' = -11
Solution ⇒ S{-11 ; 11 } or (x-11)(x+11)
4) 4x² + 144 = 0
4x² = -144
x² = -144 / 4
x² = -36
x = √-36
No solution ⇒ S = ∅
5) z²+10z+21 = 0
Δ = 10² - 4(1)(21)
Δ = 100 - 84
Δ = 16
x' = (-10+4) / 2 = -6/2 = -3
x'' = (-10-4) / 2 = -14/2 = -7
Solution ⇒ S{ -7 ; -3} or (x+3)(x+7)
<span>300.0109
I hope this helps
300=3 hundreds
.0109= 109 hundredths</span>
Answer: 1/2, 1/2, 1/4
Step-by-step explanation:
To find the fraction that the hour hand turns of a clockwise revolution, we have to find how long it is going then divide by 12
Ex. a) 11 - 5 = 6, 6/12 = 1/2 so the hour hand turns by 1/2 of a clockwise revolution
b) 8 - 2 = 6, 6/12 = 1/2 so the hour hand turns by 1/2 of a clockwise revolution
c) For this, we have to convert 1 into 13 as 1 - 10 is a negative number
13 - 10 = 3, 3/12 = 1/4 so the hour hand turns by 1/4 of a clockwise revolution
