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3 years ago

What is the three-dimensional shape of the molecule with this Lewis structure?

Chemistry

1 answer:

yKpoI14uk [10]3 years ago

4 0

Answer:

C. Trigonal planar

Explanation:

Hello!

In this case, according to the VSEPR theory, it is possible to realize that this molecule has three bonded atoms to the main carbon, one oxygen and two hydrogens. In addition, the aforementioned central carbon atom does not have any lone pairs, therefore, the molecular geometry for three bonded atoms and zero lone pairs would be trigonal planar.

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In the chemical equation Zn + 2HCL -----> ZnCl2 + H2

Norma-Jean [14]

Zinc and hydrochloric

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4 years ago

The lab procedure mentions that not all of the oxone may dissolve after being added to the water because the water may be satura

ollegr [7]

Answer:

The answer is (C) There are more solute molecules than water molecules.

Explanation:

A saturated solution is one in which no more solute can be dissolved or disintegrated into the solvent. When or if the ozone stops being dissolved in the water, it implies that the water has already taken on more ozone molecules than it can contain, meaning there are more solute molecules (ozone molecules) than there are solvent molecules (water molecules).

3 0

3 years ago

Read 2 more answers

Michelle is trying to find the average atomic mass of a sample of an unknown

GREYUIT [131]

The average atomic mass of her sample is 114.54 amu

Let the 1st isotope be A

Let the 2nd isotope be B

From the question given above, the following data were obtained:

Abundance of isotope A (A%) = 59.34%
Mass of isotope A = 113.6459 amu
Mass of isotope B = 115.8488 amu
Abundance of isotope B (B%) = 100 – 59.34 = 40.66%
Average atomic mass =?

The average atomic mass of the sample can be obtained as follow:

$Average \: atomic \: mass \: = \frac{mass \: of \: A \times A\%}{100} + \frac{mass \: of \: B \times B\%}{100} \\ \\ Average \: atomic \: mass \: = \frac{113.6459\times 59.34}{100} + \frac{115.8488\times 40.66}{100} \\ \\ Average \: atomic \: mass \: = 114.54 \: amu \\ \\$

Thus, the average atomic mass of the sample is 114.54 amu

Learn more about isotope: brainly.com/question/25868336

3 0

3 years ago

The pressure of a sample of helium is 1.556 atm in a 268.5 mL container. If the container is compressed to 112.4 mL without chan

Rainbow [258]

Answer:

a. 3.72 [atm]

Explanation:

For a gas at constant temperature, (with no change in number of molecules of the gas), we can apply Boyle's Law: $P_1V_1=P_2V_2$

$(1.556[atm])(268.5[mL])=P_2(112.4[mL])$

$\dfrac{(1.556[atm])(268.5[mL\!\!\!\!\!\!\!\!{--}])}{112.4[mL \!\!\!\!\!\!\!\!{--}]}=\dfrac{P_2(112.4[mL]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{-----})}{112.4[mL]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{-----}}$

$3.716957[atm]=P_2$

It seems like the answer should have 4 significant figures since all of the other quantities have 4 significant figures, but the closest answer choice of those provided is a. 3.72

3 0

2 years ago

How much heat do you need to raise the temperature of 100g of aluminum from 30 C to 150 C

SVEN [57.7K]

Answer:

Q = 10.8 KJ

Explanation:

Given data:

Mass of Al= 100g

Initial temperature = 30°C

Final temperature = 150°C

Heat required = ?

Solution:

Specific heat of Al = 0.90 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 150°C - 30°C

ΔT = 120°C

Q = 100g×0.90 J/g.°C× 120°C

Q = 10800 J (10800j×1KJ/1000 j)

Q = 10.8 KJ

4 0

4 years ago

Read 2 more answers