Each energy sub-level corresponds to an orbital of a different shape which describes where the electron is likely to be found
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<u>Answer:</u> The pH of the solution is 1.703
<u>Explanation:</u>
We are given:
Concentration of monochloroacetic acid = 0.31 M
The chemical equation for the dissociation of monochloroacetic acid follows:

<u>Initial:</u> 0.31
<u>At eqllm:</u> 0.31-x x x
The expression of
for above equation follows:
![K_a=\frac{[H^+][C_2H_2ClO_2^-}}{[HC_2H_2ClO_2]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BH%5E%2B%5D%5BC_2H_2ClO_2%5E-%7D%7D%7B%5BHC_2H_2ClO_2%5D%7D)
We are given:

Putting values in above equation follows:

Neglecting the negative value of 'x' because concentration cannot be negative.
To calculate the pH of the solution, we use the equation:
![pH=-\log[H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%5BH%5E%2B%5D)

Hence, the pH of the solution is 1.703
Density=mass/volume
density=330/20
density=16.5g/ml