The mole ration of two productions depends on the balanced equation which we can get from the question. And the mole ratio is equals to the ratio of number before the compounds. So the answer is 2:1.
<span>7.75% nitrogen in the sample.
The balanced reaction of HCl and NH3 is
HCl + NH3 = NH4Cl
Which means that 1 mole of HCl will neutralize 1 mole of HN3.
Since we used 83.0 ml of 0.150 m HCl, that means that we used
0.083 l * 0.150 mol/l = 0.01245 mol
So we had 0.01245 mol of NH3 which means that we had 0.01245 mol of N
Looking up the atomic weight of nitrogen, we get 14.0067. So
0.01245 * 14.0067 = 0.174383415 g
We now know that the sample had 0.17438 g of nitrogen. Divide by the original mass of the sample, getting
0.17438 / 2.25 = 0.077502222 = 7.7502222%
Rounding the result to 3 significant figures, gives us a mass percentage of 7.75% nitrogen in the original sample.</span>
Answer:
90g
Explanation:
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1. is prophase, chromatid in the nuclear envelope disappears2. metaphase, all the genetic material is condensing into chromosomes 3. anaphase, chromosomes move to opposite sides of the circle 4. telophase, the final phase two nuclei are formed