7.66g of ethyl butyrate is produced.
The reaction is
CH₃CH₂CH₂COOH + CH₃CH₂OH ----> CH₃CH₂CH₂COOCH₂CH₃
- The molar mass of butanoic acid is 88.11g/mol
- We have 7.45g of butanoic acid
- The moles of butanoic acid we have is 7.45/88.11 = 0.0845 mol
- If the yield is 100%, 1 mole of butanoic acid gives 1 mole of ethyl butyrate
- But the reaction yield is 78%
- 1 mole of butanoic acid gives 0.78 mole of ethyl butyrate
From 0.0845 mol of butanoic acid we get 0.78 x 0.0845 = 0.66 mol of ethyl butyrate.
The molar mass of ethyl butyrate is 116.16g/mol
So 0.66 x 116.16 = 7.66g
7.66g of ethyl butyrate is produced.
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Answer:
As, the temperature decreased from 40.0 °C to 0.0 °C an amount will be recrystallized and precipitated as solid crystals in the water (51.0 g - 14.0 g = 37.0 g) and 14.0 g will be dissolved in water.
Explanation:
- Firstly, we must mention that:
The solubility of KNO₃ per 100.0 g of water at 40.0 °C = 63.0 g.
The solubility of KNO₃ per 100.0 g of water at 0.0 °C = 14.0 g.
- So, at 40.0 °C, 51.0 g of KNO₃ will be completely dissolved in water.
- <em>As, the temperature decreased from 40.0 °C to 0.0 °C an amount will be recrystallized and precipitated as solid crystals in the water (51.0 g - 14.0 g = 37.0 g) and 14.0 g will be dissolved in water.</em>
No, It can't be chemical because it has something to do with being mechanical, an example of a chemical change would be some thing like metal rusting or wood turning to ash after being burned.
As given that some volume of water has been dispensed say "x mL"
The initial weight of bottle =8.4376 g
The final weight of bottle + water =28.5845 g
So weight of water transferred = 28.5845 g - 8.4376 g = 20.1469 g
Now there is a relation between density, mass and volume
density = mass / volume
Therefore
Volume = mass / density
So volume of water dispensed = mass dispensed / density =20.1469 g / 0.9967867 g/ml.
Volume of water = 20.2118467 mL
I think it's either b or c
