We have that
case <span>A)
(x – 2)(x + 2)(x</span>²<span> + 8)(x4 + 8)
(x</span>²-4)(x² + 8)(x4 + 8)
case <span>B)
(x – 2)(x – 2)(x</span>²<span> + 4)(x4 + 16)
(x-2)</span>²(x² + 4)(x4 + 16)
case <span>C)
(x – 2)(x + 2)(x</span>²<span> + 4)(x4 + 16)
(x</span>²-4)(x² + 4)(x4 + 16)
(x4 -16)(x4 + 16)
(x8-256)
case <span>D)
(x + 2)(x + 2)(x</span>²<span> + 4)(x4 + 16)
(x+2)</span>²(x² + 4)(x4 + 16)
the answer is
the option
<span>C) (x – 2)(x + 2)(x2 + 4)(x4 + 16) </span>
Answer:
find the missing numbers
Step-by-step explanation:
16<2(3x-1)<28 divide all terms by 2
8<3x-1<14 add 1 to all terms
9<3x<15 divide all terms by 3
3<x<5
x=(3,5) in interval notation
On a number line, it would be a line segment from 3 to 5 with open circles at 3 and 5.
On a coordinate system graph, it would be an infinitely high shaded plane between the vertical lines x=3 and x=5
By any chance will it be (1,1)
