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docker41 [41]
2 years ago
13

The one-to-one functions g and h are defined as follows.

Mathematics
1 answer:
ExtremeBDS [4]2 years ago
3 0

The value of g⁻¹(5) = 0, h⁻¹(x) = (x+10)/3, and the value of h(h⁻¹(5)) = 5 if  g = {(-4, 1), (0, 5), (5, -3), (8, -8)} and h(x) = 3x - 10

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have:

g = {(-4, 1), (0, 5), (5, -3), (8, -8)}

As we know,

If f(x) has an ordered pair (x, y) then its inverse of a function has (y, x).

g⁻¹ = {(1, -4), (5, 0), (-3, 5), (-8, 8)}

g⁻¹(5) = 0

h(x) = 3x - 10

h⁻¹(x) = (x+10)/3

h⁻¹(5) = 15/3 = 5

h(h⁻¹(5)) = 3(5) - 10

h(h⁻¹(5)) = 5

Thus, the value of g⁻¹(5) = 0, h⁻¹(x) = (x+10)/3, and the value of h(h⁻¹(5)) = 5 if  g = {(-4, 1), (0, 5), (5, -3), (8, -8)} and h(x) = 3x - 10

Learn more about the function here:

brainly.com/question/5245372

#SPJ1

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