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elena-s [515]
3 years ago
12

Travelling with a current, a boat covers a distance 1.5times greater than travelling against the current in the same amount of t

ime. What is the speed of the boat in still water if the speed of the current is 1.5 mph
Mathematics
1 answer:
slega [8]3 years ago
3 0
Let the speed of the current equal c
and the speed of the boat in still water equal b.

b + c = 1.5 (b - c)
b + c = 1.5b - 1.5c
0.5b = 2.5c
b = 5c

The speed of the current is 1.5 mph so
b = 5 * 1.5 = 7.5 mph
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<h2><em><u>to</u></em><em><u> </u></em><em><u>smome</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>your</u></em><em><u> </u></em><em><u>body</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>difference</u></em><em><u> </u></em><em><u>between</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>difference</u></em><em><u> </u></em><em><u>between</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>person</u></em><em><u> </u></em><em><u>who</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>good</u></em><em><u> </u></em><em><u>thing</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>smome</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>few</u></em><em><u> </u></em><em><u>people</u></em><em><u> </u></em><em><u>are</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>different</u></em><em><u> </u></em><em><u>type</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>you</u></em><em><u> </u></em><em><u>are</u></em><em><u> </u></em><em><u>not</u></em><em><u> </u></em><em><u>sure</u></em><em><u> </u></em><em><u>how</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>make</u></em><em><u> </u></em><em><u>them</u></em><em><u> </u></em><em><u>better</u></em><em><u> </u></em><em><u>or</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>person</u></em><em><u> </u></em><em><u>with</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>better</u></em><em><u> </u></em><em><u>sense</u></em><em><u> </u></em><em><u>than</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>other</u></em><em><u> </u></em><em><u>person</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>different</u></em><em><u> </u></em><em><u>type</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>you</u></em><em><u> </u></em><em><u>are</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>good</u></em><em><u> </u></em><em><u>relationship</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>difference</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>difference</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>difference</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>difference</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>that</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>smome</u></em><em><u> </u></em></h2>
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Answer:

She ordered 80 carnations, 50 roses, and 70 daisies.

Step-by-step explanation:

Let x = number of carnations, y = number of roses, and z = number of daisies.  This problem gives us three equations.

 

First, remember that we multiply the price of each flower by the number bought then add up the subtotals, that gives the total amount paid.

Therefore,

1.50x + 5.75y + 2.60z = 589.50

 

Second, the sum of the numbers purchased is the total bought. Therefore,

x + y + z = 200

 

Finally, there are 20 fewer roses than daisies. Therefore,

y = z - 20

 

If you substitute z - 20 in for y in the first two equations, you can rewrite them so they only have x and z.

 

1.50x + 5.75(z - 20) + 2.60z = 589.50

1.50x + 5.75z - 115 + 2.60z = 589.50

1.50x + 8.35z = 704.50

 

x + (z - 20) + z = 200

x + 2z - 20 = 200

x + 2z = 220

 

If you solve the rewrite second equation for x, you get x = 220 - 2z.  Therefore, you can substitute 220 - 2z in for x in the rewritten first equation, and then solve for z.

 

1.50 (220 - 2z) + 8.35z = 704.50

330 - 3z + 8.35z = 704.50

330 + 5.35z = 704.50

5.35z = 374.50

z = 70

 

If you have z = 70, then x = 220 - 2(70) = 80 and y = 70 - 20 = 50.

 

She ordered 80 carnations, 50 roses, and 70 daisies.

*HOPE THIS HELPED!!! :D)

4 0
3 years ago
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