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2 years ago

7

A small home speaker produces 0.200 ~\text{W}0.200 W of acoustical power. (This is achieved, for example, by a 10-Watt speaker o

perating at 2% electrical efficiency). If the speaker projects sound uniformly in all directions, what is the loudness of the sound (in dB) at a distance of 0.668 ~\text{m}0.668 m from the speaker?

1 answer:

Anika [276]2 years ago

4 0

Answer:

i dont speak english

Step-by-step explanation:

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velikii [3]

Answer:

lol 4

Step-by-step explanation:

one one one one equals four

8 0

2 years ago

The width of a rectangle is 7y -7.5 feet and the length is 7.5y + 8 feet. Find the perimeter of the rectangle

galben [10]

Perimeter = length + length + width + width.

7y-7.5 + 7y-7.5 + 7.5y+8 + 7.5y +8

Combine like terms:

29y+1

The perimeter is 29y + 1 feet

5 0

2 years ago

What is 1 2/3 multiple 2/3

Flauer [41]

Answer:

$1\frac{1}{9}$

Step-by-step explanation:

Given the following question:

$1\frac{2}{3} \times\frac{2}{3}$

In order to multiply the two, we have to convert the mixed number into a improper fraction and then multiply the numerator by the numerator, the denominator by the denominator.

$1\frac{2}{3} =3\times1=3+2=\frac{5}{3}$
$\frac{5}{3} \times\frac{2}{3}$
$5\times2=10$
$3\times3=9$
$=\frac{10}{9}$

<u>Convert the improper fraction into a mixed number:</u>

$\frac{10}{9}$
$\frac{10}{9} =10\div9=1\frac{1}{9}$
$=1\frac{1}{9}$

Your answer is "1 1/9."

Hope this helps.

7 0

1 year ago

The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha

Xelga [282]

Answer:

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

Step-by-step explanation:

Let suppose that function $f$ is continuous and integrable in the given intervals, by integral definition of average we have that:

$\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6$ (1)

$\frac{1}{5-3} \int\limits^{5}_{3} {f(x)} \, dx = 20$ (2)

By Fundamental Theorems of Calculus we expand both expressions:

$\frac{F(3)-F(-2)}{3-(-2)} = -6$

$F(3) - F(-2) = -30$ (1b)

$\frac{F(5)-F(3)}{5-3} = 20$

$F(5) - F(3) = 40$ (2b)

We obtain the average value of $f$ over the interval $[-2, 5]$ by algebraic handling:

$F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)$

$F(5) - F(-2) = 10$

$\frac{F(5)-F(-2)}{5-(-2)} = \frac{10}{5-(-2)}$

$\bar f = \frac{10}{7}$

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

4 0

2 years ago

K is the midpoint of a line segment JL. If JK= 6x + 7 and KL = 9x-2, find the length of JL

Korvikt [17]

Answer:

x = 3

Step-by-step explanation:

6x + 7 = 9x - 2

-3x = -9

x = 3

3 0

1 year ago