Answer:
Multiply all the cm and u will get the answer.
This problem can be readily solved if we are familiar with the point-slope form of straight lines:
y-y0=m(x-x0) ...................................(1)
where
m=slope of line
(x0,y0) is a point through which the line passes.
We know that the line passes through A(3,-6), B(1,2)
All options have a slope of -4, so that should not be a problem. In fact, if we check the slope=(yb-ya)/(xb-xa), we do find that the slope m=-4.
So we can check which line passes through which point:
a. y+6=-4(x-3)
Rearrange to the form of equation (1) above,
y-(-6)=-4(x-3) means that line passes through A(3,-6) => ok
b. y-1=-4(x-2) means line passes through (2,1), which is neither A nor B
****** this equation is not the line passing through A & B *****
c. y=-4x+6 subtract 2 from both sides (to make the y-coordinate 2)
y-2 = -4x+4, rearrange
y-2 = -4(x-1)
which means that it passes through B(1,2), so ok
d. y-2=-4(x-1)
this is the same as the previous equation, so it passes through B(1,2),
this equation is ok.
Answer: the equation y-1=-4(x-2) does NOT pass through both A and B.
Answer:
AC = 3.72 units
Angles:
A = 132.6°
C = 27.4°
Step-by-step explanation:
AC² = 5² + 8² - 2(5)(8)cos(20)
AC² = 13.82459034
AC = 3.718143399
3.718143399/sin20 = 8/sinA
sinA = 0.7358944647
A = 180 - 47.38285134
A = 132.6171487
3.718143399/sin20 = 5/sinC
sinC = 0.4599340405
C = 27.38285134
About 4.65 miles. Multiply 3 1/2 (3.5) by 1 1/3 (1.33) and thats how you get the answer
Here’s an explanation! let me know if you need further clarification
