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Shtirlitz [24]
3 years ago
9

Find the equation of the line

Mathematics
2 answers:
PolarNik [594]3 years ago
8 0

Answer:

y = 10x +

the picture is cut short so I can't help with the next box.

cluponka [151]3 years ago
6 0
Y = 10x +

Explanation: because I know
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Three boxes of supplies have an average (arithmetic mean) weight of 7 kilograms and a median weight of 9 kilograms. What is the
GuDViN [60]

Answer:

3

Step-by-step explanation:

A) 1

(B) 2

(C) 3

(D) 4

(E) 5

Mean is a measure of central tendency. It is the average of a set of numbers. It is determined by adding the numbers together and dividing it by the total number

Mean = sum of numbers / number of observation

sum of numbers = 3 x 7 = 21

Median is the number that is at the center or middle of a set of obervations

x +  9+ y = 21

x= lowest number

y = highest number

x + y = 21 - 9

x + y = 12

If x = 1 y = 11

if x = 2 y = 10

if x = 3 y = 9

if x = 4 y = 8

the first 3 are plausible and the median would still be 9 if x = 4, median would be 8

3 0
2 years ago
Sold 685 boxes of cookies about how many boxes are they sold rounded to the nearest ten
MissTica

Answer:

690

Step-by-step explanation:

Round from the tens place.

8 0
3 years ago
48a2 + 32a2 + 16a by 4a?
lbvjy [14]

(48a^3 + 32a^2 + 16a) / 4a = ?

48a^3 / 4a = 12a^2

32a^2 / 4a = 8a

16a / 4a = 4

so

(48a^3 + 32a^2 + 16a) / 4a = 12a^2 + 8a + 4

Answer is D. 12a^2 + 8a + 4

7 0
3 years ago
Read 2 more answers
find the slooe word problem. A friend gifts you a pet rock collection. You decide to grow the collection by 10 pet rocks every m
babymother [125]
I disagree with the student because the slope is the rate of change. The slope would be 10 because the rocks are increasing by 10 every month.
8 0
2 years ago
find three consecutive odd integers such that the sum of the smallest number and middle number is 27 less than 3 times the large
katrin2010 [14]

A generic odd number can be written as

2k+1,\quad k \in \mathbb{Z}

Since there is an odd number every two numbers, three consecutive odd numbers will be

2k+1,\quad 2k+3,\quad 2k+5

Now let's make up the equations: the sum of the first two is

(2k+1)+(2k+3)

And 27 less than 3 times the largest is

3(2k+5)-27

These two must be the same, so we have

(2k+1)+(2k+3)=3(2k+5)-27 \iff 4k+4 = 6k+30-27 \iff 4k+4=6k+3

Subtracting 4k and 3 from both sides gives

1=2k \iff k=\dfrac{1}{2}

Which means that the problem has no solution.

To confirm this hypothesis, we can observe that, on the left hand side, we have the sum of two odd numbers, which is even

On the right hand side, we have an odd number, multiplied by 3 (still odd), take away 27 (still odd).

So, the left hand side is even, and the right hand side is odd. They can't be the same number.

7 0
3 years ago
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