<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em><em>⤴</em>
<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>.</em><em>✔</em><em>✔</em><em>:</em><em>)</em>
Take a look at the picture i sent you
Answer:
8
Step-by-step explanation:
To one decimal place:


So there are eight integers between 2√10 and 10√2: 7, 8, 9, 10, 11, 12, 13, and 14.
We are given that there are a total of 78 students. If we set the following variables:

Then, the sum of all of these must be 78, that is:

Since there are 15 in chemistry and physics and 47 in chemistry, we may replace that into the equation and we get:

Simplifying:

Now we solve for P by subtracting 62 on both sides:

Therefore, there are 16 students in physics
When you add an integer and a natural number, you always get an integer.