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sweet-ann [11.9K]
3 years ago
10

Casey spent $2.50 on a snack,$1.24 on gum,$3.76 on a comic book, and $5.50 on lunch. Use mental math to find the total amount he

spent.
Mathematics
1 answer:
stellarik [79]3 years ago
5 0

Answer:

$13

Step-by-step explanation:

Given data

$2.50 on a snack,

$1.24 on gum,

$3.76 on a comic book, and

$5.50 on lunch

Total expenses will be

=2.5+1.24+3.76+5.50

=$13

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Leo has $4.80 in dimes a d quarters he has 6 more dimes than quarters how many quarters does he have
Kryger [21]

Answer:

Step-by-step explanation:

he has 4.80 in dimes and quarters....dimes (d) are worth 0.10 and quarters (q) are worth 0.25

0.10d + 0.25q = 4.80

he has 6 more dimes then quarters

d = q + 6

====================

d = q + 6...so we sub q + 6 in for d, back into the other equation

0.10(q + 6) + 0.25q = 4.80

0.10q + 0.60 + 0.25q = 4.80

0.35q = 4.80 - 0.60

0.35q = 4.20

q = 4.20 / 0.35

q = 12 <====== there is 12 quarters

d = q + 6

d = 12 + 6

d = 18 <===== there is 18 dimes

6 0
3 years ago
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When three points lie on the same line
anyanavicka [17]
When three points are on the same line it’s collinear,. we’re in the same class LOL
3 0
2 years ago
What is the missing constant term in the perfect square that starts with x^2 - 20x
Andre45 [30]

Answer:

100

Step-by-step explanation:

To make a perfect square trinomial, you want to divide the use the following equation to find the missing constant:

(\frac{b}{2} )^{2} when the quadratic is in standard form.

In this case, we would divide -20 by 2 and square it

-20/2 = -10

(-10)^2 = 100

4 0
3 years ago
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Help? Would be appreciated!!
MaRussiya [10]

Answer:

a. 5 ones

b.8 hundreds

c.9 thousandths

d.1 tenths

e. 7 hundreths

f. 1 millions

hope that helps you

7 0
2 years ago
What are the roots of the quadratic equation below?<br> x2 + 2x= -5
muminat

Answer:

No real root.

Complex roots:

x = -1 \pm 2i

Step-by-step explanation:

x^2 + 2x = -5

x^2 + 2x + 5 = 0

There are no two integers whose product is 5 and whose sum is 2, so this trinomial is not factorable. We can use the quadratic formula.

x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}

x = \dfrac{-2 \pm \sqrt{2^2 - 4(1)(5)}}{2(1)}

x = \dfrac{-2 \pm \sqrt{4 - 20}}{2}

x = \dfrac{-2 \pm \sqrt{-16}}{2}

Since we have a square root of a negative number, there are no real roots. If you have learned complex numbers, then we can continue.

x = \dfrac{-2 \pm 4i}{2}

x = -1 \pm 2i

7 0
3 years ago
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